All categories

3 years ago

List the sides of the triangle in order from largest to smallest

Mathematics

1 answer:

Alona [7]3 years ago

7 0

Answer:

Step-by-step explanation:

The smallest side is BC

The next smallest side is AB

The largest side is AC

You might be interested in

Tell whether the ordered pair (- 3, 0) is a solution of the given system. - 2x + 2y >= 4an y >= 2x - 6

alukav5142 [94]

Answer:

The ordered pair is a solution.

Step-by-step explanation:

Plug x = -3 and y = 0 into the 2 inequalities and see if they fit:

-2x + 2y >= 4

-2(-3) + 2(0) = 6 which is > 4 so this one fits.

y>= 2x - 6

0 >= 2*-3) - 6 = -12 which also fits.

8 0

3 years ago

Read 2 more answers

G verify that the divergence theorem is true for the vector field f on the region

Alenkasestr [34]

$\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1$

Converting to spherical coordinates, we have

$\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi$

On the other hand, we can parameterize the boundary of $E$ by

$\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle$

with $0\le u\le2\pi$ and $0\le v\le\pi$ . Now, consider the surface element

$\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv$
$\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv$
$\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv$

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

$\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv$
$=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi$

as required.

3 0

3 years ago

Write the equation of the line in slope- intercept and point-slope form.

AnnZ [28]

Answer:

Step-by-step explanation:

As we move from the x-intercept (-2, 0) to the y-intercept (0, 4), x increases by 2 (this is the run) and y by 4 (this is the rise). Thus, the slope of this line is

m = rise/run = 4/2 = 2.

Given the y-intercept (0, 4) and the slope (2), the slope-intercept form of the equation of this line is y = 2x + 4.

From this we get the point-slope form:

y = 2x + 4 becomes y - 4 = 2(x - 0), or just y - 4 = 2x.

3 0

2 years ago

Receive 5% commission sold for $ 65000 much is my commission

natka813 [3]

Answer: $3,250

Step-by-step explanation:

5% is the same as 0.05

$65,000 x 0.05 = $3,250

5 0

2 years ago

Find the circumference and the area of a circle with radius 5mm.

Archy [21]

Answer: 31.4 mm

Step-by-step explanation:

C=2πr

2(3.14)(5)

2(15.7)

31.4

8 0

3 years ago