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balu736 [363]
3 years ago
6

Graph the hyperbola y^2/16-x^2/9=1. What type of transverse axis does it have?

Mathematics
1 answer:
gulaghasi [49]3 years ago
3 0
<span>Center(0,0)
a^2=16
a=4
b^2=9

b=3
c^2=a^2+b^2=16+9=25
c=√25=5</span>
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(\frac{1}{K}) +  (\frac{1}{K-3}) = (\frac{1}{2})\\\implies  \frac{(K-3) + K}{K (K-3)}  = (\frac{1}{2})\\\implies 2(2K -3) = K^2 - 3K\\\implies k^2 - 3K -4K +6 = 0\\\implies K^2 - 7K  + 6=  0\\\implies K^2 - 6K - K  + 6=  0\\\implies K(K-6) -1(K - 6)=  0\\\implies (K-6)(K-1) = 0

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