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Varvara68 [4.7K]
3 years ago
9

WILL MARK BRANLIEST 50 POINTS PLEASE HELP ( CORRECT ANSWER ) Simplify. 30k2 + 6k 5k + k

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
8 0
Simplified answer would be 60k^2+k

and you get that answer by combining like terms, Good Luck! 

aleksandr82 [10.1K]3 years ago
7 0
The answer is 60k2 + k. hope this helps :)
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chubhunter [2.5K]

Answer:

68.26% of the parts will have lengths between 3.8 in. and 4.2 in.

Step-by-step explanation:

The lengths of a lawn mower part are approximately normally distributed

\mu = 4

Standard deviation =\sigma =0.2

We are supposed to find  What percentage of the parts will have lengths between 3.8 in. and 4.2 in . i.e. P(3.8<x<4.2)

Formula : Z=\frac{x-\mu}{\sigma}

At x = 3.8

Z=\frac{3.8-4}{0.2}

Z=-1

Refer the z table for p value

p value =0.1587

At x =4.2

Z=\frac{4.2-4}{0.2}

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Refer the z table for p value

p value =0.8413

P(3.8<x<4.2)=P(x<4.2)-P(x<3.8)=0.8413-0.1587=0.6826

So, 68.26% of the parts will have lengths between 3.8 in. and 4.2 in.

3 0
3 years ago
If a &lt; 0 then the graph opens_____​
telo118 [61]

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down

Step-by-step explanation:

Assuming this is for a parabola

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4 0
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Step-by-step explanation:

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2 years ago
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expeople1 [14]

Answer:

The area is 432cm squared.

Step-by-step explanation:

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6 0
3 years ago
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