Answer:
B - $41,500
Step-by-step explanation:
After Subtracting his liabilities this is what I got.
Hope this Helps!
:D
Answer:
MRS. White graded 51 papers.
Step-by-step explanation:
85/100= 0.85
0.85 x 60 = 51
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
Answer:
Roots are : 1, -7 and -7
Step-by-step explanation:
When we put x = -1 in F(x) it is equal to 0
Thus, (x + 1) is factor of given function.
When we divide F(x) by (x + 1) it gives the value (x² - 6x - 7)
factorizing the work x² - 6x - 7 by middle term splitting.
> x² - 6x - 7 = x² - 7x + x - 7
> x(x - 7) + 1(x - 7)
> (x + 1) (x - 7)
then, x³ - 5x² - 13x - 7 = (x + 1)(x + 1)(x - 7)
x = -1, -1, 7 the factor.
D and C is the answers.
Step-by-step explanation:
The equation would be h=1m+42 and the answer is 78 I think
