Step-by-step explanation:
5,555 can be rounded up to 6,000 because the 5 next to the five thousand will make it go up. while the 4,444 will round to 4,000 . I don't have a clear answer but I hope this helps.
The actual cost to the store = $140
Percentage of markup = 25%
Amount of markup in cost = (25/100) * 140 dollars
= 35 dollars
Then
Sell price in the store = (35 + 140) dollars
= 175 dollars
So the sell price of the product at the store after addition of the markup price will be $175.
Well first do 20 children minus 8 girls to find how many boys there are:
20-8=16
So there are 16 boys. Therefore we can write the ratio of girls to boys as:
8/16
Then we can simplify this ratio by dividing it by 8 to get:
1/2
So the answer is the ratio of girls to boys in the group in simplest form is 1/2.
<h3>Answer:</h3>
none of these has "no solution"
<h3>Explanation:</h3>
A. The solution is (8/3, 3)
B. The second equation is -1/2 times the first, so these describe the same line. The system has an <em>infinite number of solutions</em>.
C. The solution is (-4, -2)
D. The solution is (4, -2)
E. The second equation is 2 times the first, so these describe the same line. The system has an <em>infinite number of solutions</em>.
_____
A system of equations will have "no solution" when it describes parallel lines—lines that do not intersect. In standard form, such equations are recognizable by their different constants. For example,
- 3x -4y = -4
- 3x -4y = 20 . . . . . . 20 is different from -4
have different constants, so the equations describe parallel lines.
We could multiply one of these by -2 and the system would still be "inconsistent"—having no solution.
Answer:
1. 1343 years
2. 9 hours
3. 39 years
Step-by-step explanation:
1. Given, half-life of carbon = 5730 years.
∴ λ = 0.693/half-life of carbon = 0.693/5730 = 0.000121
If N₀ = 100 then N = 85
Formula:- N = N₀*e^(-λt)
∴ 85 = 100 * e^(-0.000121t)
∴㏑(-0.85)=-0.000121t
∴ t = 1343 years
2. Given half-life of aspirin = 12 hours
λ = 0.693/12 = 0.5775
Also N₀ = 100 then 70 will disintegrate and N = 30 will remain disintegrated.
∴ 70 = 100 *e^(-0.05775t)
0.70 = e^(-0.05775t)
㏑(0.70) = -0.05775t
∴ t = 9 hours
3. The population of the birds as as A=A₀*e^(kt)
Given that the population of birds fell from 1400 from 1000, We are asked how much time it will take for the population to drop below 100, let that be x years.
The population is 1400 when f = 0, And it is 1000 when f = 5
We can write the following equation :
1400 = 1000e^(5t).
∴1400/1000 = e^(5k)
∴ k = ㏑(1.4)/5
We need to find x such that 1400/100 = e^(xk)
14 = e^(xk)
∴ x = 39 years