The expression into a single logarithm is ![log[(x)^{10}][(2)^{30}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%282%29%5E%7B30%7D%5D)
Step-by-step explanation:
Let us revise some logarithmic rules
∵ 10 log(x) + 5 log(64)
- At first re-write 10 log(x)
∴ 10 log(x) = 
- Then re-write 5 log(64)
∴ 5 log(64) = 
∴ 10 log(x) + 5 log(64) =
+ 
- Use the 3rd rule above to make it single logarithm
∵
+
= ![log[(x)^{10}][(64)^{5}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%2864%29%5E%7B5%7D%5D)
∴ 10 log(x) + 5 log(64) = ![log[(x)^{10}][(64)^{5}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%2864%29%5E%7B5%7D%5D)
∵ 64 = 2 × 2 × 2 × 2 × 2 × 2
∴ We can write 64 as 
∴ 
- Multiply the two powers of 2
∴ 
∴ 10 log(x) + 5 log(64) = ![log[(x)^{10}][(2)^{30}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%282%29%5E%7B30%7D%5D)
The expression into a single logarithm is ![log[(x)^{10}][(2)^{30}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%282%29%5E%7B30%7D%5D)
Learn more:
You can learn more about the logarithmic functions in brainly.com/question/11921476
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Answer:
x=14 , y = 21
Step-by-step explanation:
y=x-7...............1
5x+2y=7......2
reset eqn .....2
2y=-5x+7
so; y=-x-7 ×5
2y=-5x+7 ×1
5y = -5x -35
2y = -5x +7
5y-2y = -5 + 5 -35-7
<u>3y</u> = - <u>42</u>
3 3
y = 14
sub y=14 into eqn ...........1
y = -x -7
14 = - x -7
14 +7 = - x
-21 = x
x = 14 , y =-21
Answer:
40x-11
Step-by-step explanation:
Since it is perpendicular to y=3x-1, the slope must be a negative reciprocal.
there the slope of the perpendicular line is

So now we have,

To find b, we use the point that the line passes through and substitute it to the y and x values.

which would give us b=5/3
Therefore, the equation of the line is