Huh? this is very confusing 12
Assuming that b>0 and c>0:
log(a)=3×log(b)-2×log(c)=
log(b³)-log(c²)=
log(b³/c²)
Hence a=b³/c²
Given that
the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.
And we need to find What is the minimum weight of the middle 95% of the players?
Explanation -
Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.
Two standard deviations = 2 x 25 pounds = 50 pounds
So the minimum weight = 200 pounds - 50 pounds = 150 pounds
Hence the final answer is 150 pounds.
Answer:
= 124 ft
Step-by-step explanation:
Perimeter of a rectangle is
P = 2(l+w)
We know the length is 13 and the width is 49
P = 2(13+49)
=2(62)
= 124 ft
