The expression for five groups of a number added to seventeen.
Let the number be X
Five groups of the number will be 5X
The required expression will be
5(X) +17
The statement that 99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest is false.
A confidence interval (CI) is essentially a range of estimates for an unknown parameter in frequentist statistics. The most frequent confidence level is 95%, but other levels, such 90% or 99%, are infrequently used for generating confidence intervals.
The confidence level is a measurement of the proportion of long-term associated CIs that include the parameter's true value. This is closely related to the moment-based estimate approach.
In a straightforward illustration, when the population mean is the quantity that needs to be estimated, the sample mean is a straightforward estimate. The population variance can also be calculated using the sample variance. Using the sample mean and the true mean's probability.
Hence we can generally infer that the given statement is false.
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Answer:n= 1/3d - 2/3m
Step-by-step explanation:
d=2m+3n
Step 1: Flip the equation.
2m+3n=d
Step 2: Add -2m to both sides.
2m+3n+−2m=d+−2m
3n=d−2m
Step 3: Divide both sides by 3.
3n/3 = d-2m/3
Therefore
n= 1/3d - 2/3m
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Answer:
n = d - 2m
3*
Step-by-step explanation:
First we want to get n alone on one side, so we should subtract 2m from both side;
d = 2m + 3n
3n = d - 2m
Now to get n by itself, we need to divide by 3 from both sides;
3n = d - 2m
n = d - 2m
3*
*Pretend there is a fraction bar between d - 2m and 3
Step-by-step explanation:
50779 / 590 = 86.06610169
But, you can round this to equal 86.1.
Answer is 7
Step by step explanation
|-7|=7
