Anyone know what a vertical zigzag

What is the slope of the cone

dimaraw [331]

I believe it’s 2 because rise/run and 14/7 = 2

5 0

4 years ago

Brainliest if correct

marysya [2.9K]

Answer:

w=4

Step-by-step explanation:

28=14w-7w whenever you work it out it equals w=4... happy to help :)

8 0

2 years ago

Read 2 more answers

Tomas wrote the equation y = 3x 3/4+. When Sandra wrote her equation, they discovered that her equation had all the same solutio

Archy [21]

3x-y= -3/4 this is the answer

6 0

3 years ago

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The mean of a population is 74 and the standard deviation is 16. The shape of the population is unknown. Determine the probabili

uysha [10]

Answer:

(a) P( $\bar X$ $\geq$ 76) = 0.2327

(b) P(73 < $\bar X$ < 75) = 0.5035

(c) P( $\bar X$ < 74.8) = 0.77035

Step-by-step explanation:

We are given that the mean of a population is 74 and the standard deviation is 16.

Assuming the data follows normal distribution.

Let $\bar X$ = sample mean

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 74

$\sigma$ = standard deviation = 16

n = sample size

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

(a) Probability that a random sample of size 34 yielding a sample mean of 76 or more is given by = P( $\bar X$ $\geq$ 76)

P( $\bar X$ $\geq$ 76) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{76-74}{\frac{16}{\sqrt{34} } }$ ) = P(Z $\geq$ 0.73) = 1 - P(Z < 0.73)

= 1 - 0.7673 = 0.2327

The above probability is calculated by looking at the value of x = 0.73 in the z table which has an area of 0.7673.

(b) Probability that a random sample of size 120 yielding a sample mean of between 73 and 75 is given by = P(73 < $\bar X$ < 75) = P( $\bar X$ < 75) - P( $\bar X$ $\leq$ 73)

P( $\bar X$ < 75) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{75-74}{\frac{16}{\sqrt{120} } }$ ) = P(Z < 0.68) = 0.75175

P( $\bar X$ $\leq$ 73) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{73-74}{\frac{16}{\sqrt{120} } }$ ) = P(Z $\leq$ -0.68) =1 - P(Z < 0.68)

= 1 - 0.75175 = 0.24825

Therefore, P(73 < $\bar X$ < 75) = 0.75175 - 0.24825 = 0.5035

The above probability is calculated by looking at the value of x = 0.68 in the z table which has an area of 0.75175.

(c) Probability that a random sample of size 218 yielding a sample mean of less than 74.8 is given by = P( $\bar X$ < 74.8)

P( $\bar X$ < 74.8) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{74.8-74}{\frac{16}{\sqrt{218} } }$ ) = P(Z < 0.74) = 0.77035

The above probability is calculated by looking at the value of x = 0.74 in the z table which has an area of 0.77035.

7 0

3 years ago

I really need some math help. How do I do this?

lukranit [14]

First, find the value of x. Then, use the measures of the arcs to find the value of w.

When two chords intersect, the measure of the internal angle is equal to the average of the arcs that it encloses:

$c=\frac{1}{2}(a+b)$

Since the angle of 70° encloses arcs of 60° and x°, then:

$70=\frac{1}{2}(60+x)$

Solve for x:

$\begin{gathered} x=2\times70-60 \\ =140-60 \\ =80 \end{gathered}$

The sum of the measures of the arcs of a circle must be equal to 360°. Then:

$w+x+79+60=360$

Substitute x=80 and solve for w:

$\begin{gathered} \Rightarrow w+80+79+60=360 \\ \Rightarrow w+219=360 \\ \Rightarrow w=360-219 \\ \Rightarrow w=141 \end{gathered}$

Therefore, the value of w is:

$141^{\circ}$

5 0

1 year ago