The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
9. One is 6 over par, the other is three under, so subtract first-second = 6-(-3) = 9
Answer:
38
Step-by-step explanation:
j/-2=-19
j=38
Answer:
The answer is 1.2
Step-by-step explanation:
Hope this helps
