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Natasha_Volkova [10]

3 years ago

15

Hector waters his lawn if it does not get least 1 1/2 inches of rain each week. it has rained 3/8 inch already this week. which

inequality represents the number of inches of rain,r, hector lawns still needs so that he won't have to water it
( ITS 1 AND 1/2 INCHES OF RAIN THIS WEEK AND NOT 11/2)

2 answers:

ValentinkaMS [17]3 years ago

4 0

The Answer Is r > 1 1/8 or r > 1 And 1/8.

Andrew [12]3 years ago

3 0

It is r 1 less than or equal to 1/8

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2 intersecting lines are shown. A line with points M, H, K intersects a line with points L, H, J at point H. 4 angles are create

yulyashka [42]

Answer:

m = 10

Step-by-step explanation:

According to the picture attached, we can see the angles formed.

The angle on the top (5m+100) is sided with the angle 2m+10. This means that they are supplementary angles, their sum is 180°.

So,

5m+100+2m+10 = 180

5m+2m=180-100-10

7m = 70

m = 10

5 0

3 years ago

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A company produces and sells CDs. There is a fixed cost of $2000 and $5 per CD manufactured. The manufacturer sells each CD for

OlgaM077 [116]

Call the production cost 'C', the revenue 'R' and the number of CDs 'n':

C=2000+5n
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3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

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2 years ago

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Sati [7]

I think the answer is 37.7

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3 years ago

Can someone please help me real quick?

Ivahew [28]

Answer:

Big square - unshaded = shaded

((8+4)X(10+5))-(10X8)=100

Answer: 100

Step-by-step explanation:

8 0

2 years ago