Answer:
<h2>x = 28</h2><h2>CE = 132</h2><h2 />
Step-by-step explanation:
|<------------- CE -------------------->|
C-------------------D-------------------E
2x + 10 3x - 18
2x + 10 = 3x - 18
2x - 3x = -18 - 10
-x = -28
x = 28
CE = 2x + 10 + 3x - 18
CE = 2(28) + 10 + 3(28) - 18
CE = 56 + 10 + 84 - 18
CE = 132
50 People played an instrument. Every 10 people is represented as a 1 in the fraction. 5=50
Answer:
Step-by-step explanation:
1. p║ q
50+130 = 180
If the same side interior angles are supplementary angles then the lines are parallel.
2. p║ q
70 = 70
If the corresponding angles are congruent the lines are parallels.
4. p║ q
x = x
If alternating exterior angles are congruent then the lines are parallel.
5. we do not know if p is parallel with q
We have given that 2 vertical angles are congruent yet that is not enough to tell us about the relation between the 2 lines.
7. For the lines p and q to be parallel we need the corresponding angles 3x and 45 to be congruent so therefore equal in measure.
3x= 45 , divide both sides by 3
x= 15
For x = 15 the p║ q
8. For the lines p and q to be parallel we need the corresponding angles 120 and (2x+10) to be congruent so therefore equal in measure.
2x+10 = 120, subtract 10 from both sides
2x = 110, divide both sides by 2
x = 55
For x = 55 the p║ q
Answer:
11
Step-by-step explanation:
140-129=11
Answer:
10.50°C
Step-by-step explanation:
Given x = 2 + t , y = 1 + 1/2t where x and y are measured in centimeters. Also, the temperature function satisfies Tx(2, 2) = 9 and Ty(2, 2) = 3
The rate of change in temperature of the bug path can be expressed using the composite formula:
dT/dt = Tx(dx/dt) + Ty(dy/dt)
If x = 2+t; dx/dt = 1
If y = 1+12t; dy/dt = 1/2
Substituting the parameters gotten into dT/dt we will have;
dT/dt = 9(1)+3(1/2)
dT/dt = 9+1.5
dT/dt = 10.50°C/s
Hence the rate at which the temperature is rising along the bug's path is 10.50°C/s
