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Lostsunrise [7]
3 years ago
12

The youth group is going on a trip to the state fair. The trip costs $63. Included in that price is $13 for a concert ticket and

the cost of 2 passes, one for the rides and one for the game booths. Each of the passes costs the same price. Write an equation representing the cost of the trip, and determine the price of one pass. Solve your equation by showing your work and steps. i need someone to break it down step by step to help me understand
Mathematics
2 answers:
Anettt [7]3 years ago
8 0
63-13=50   50 divede by 2 cu is the same price for both 25 and 25
25+25+13 GAMES AND RIDE are 25 each and the concert 13
forsale [732]3 years ago
3 0

Ok,

The total is 63$:

= 63

It shows us one of the numbers for the equation, 13

+ 13 = 63

Two passes together plus the thirteen equals the total of 63$

the price of the pass is unknown, so we can use a variable to figure it out:

2x + 13 = 63

Now we solve

First subtract 13 from both sides:

2x + 13 - 13 = 63 - 13

Then divide both sides by 2:

2x ÷ 2 = 50 ÷ 2

Now we get our answer:

x = 25

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Bryan does indeed have enough money to pay back Jennifer.
We have the 2 numbers -15 and 20. The absolute values of those numbers are 15 and 20.

All we have to do is subtrace 15 from 20. We have the result of positive 5, meaning Bryan will still have $5 left over.
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50j

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The athlete drank 80% of his water bottle in the first 15 minutes of his workout. If the bottle held 16.9 ounces of water, how m
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13.52 ounces of water

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Which of the following is a solution to the inequality 3x-y<5
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Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
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