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Lostsunrise [7]
4 years ago
12

The youth group is going on a trip to the state fair. The trip costs $63. Included in that price is $13 for a concert ticket and

the cost of 2 passes, one for the rides and one for the game booths. Each of the passes costs the same price. Write an equation representing the cost of the trip, and determine the price of one pass. Solve your equation by showing your work and steps. i need someone to break it down step by step to help me understand
Mathematics
2 answers:
Anettt [7]4 years ago
8 0
63-13=50   50 divede by 2 cu is the same price for both 25 and 25
25+25+13 GAMES AND RIDE are 25 each and the concert 13
forsale [732]4 years ago
3 0

Ok,

The total is 63$:

= 63

It shows us one of the numbers for the equation, 13

+ 13 = 63

Two passes together plus the thirteen equals the total of 63$

the price of the pass is unknown, so we can use a variable to figure it out:

2x + 13 = 63

Now we solve

First subtract 13 from both sides:

2x + 13 - 13 = 63 - 13

Then divide both sides by 2:

2x ÷ 2 = 50 ÷ 2

Now we get our answer:

x = 25

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Step-by-step explanation:

<u>Given</u>:

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  g(x) = 3x^2 +2x -4

<u>Find</u>:

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<u>Solution</u>:

Substitute per the function definitions.

  f(g(x)) = f(3x^2 +2x -4) = -(3x^2 +2x -4) -7

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Translating a function up is very simple, all you need to do here is add 8.

If you want to think of it logically,

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the whole right side of the function here can be our output. If x is 8, then the output, or height, is also 8. if you wanted to translate that up to 10, you'd simply need to add 2 to it, meaning x+2. Then, at any given point on the function, it'd be 2 higher than it would be otherwise.

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Equation:

{x}^{2}   +  {y}^{2} +  2x  - 2y   -  35= 0

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )

Plug in the points to get:

( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )

( \frac{ -2}{2}, \frac{ 2}{2} )

(  - 1, 1)

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

r =  \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }

r =  \sqrt{ {(5 -  - 1)}^{2} + {( - 2- - 1)}^{2} }

r =  \sqrt{ {(6)}^{2} + {( - 1)}^{2} }

r =  \sqrt{ 36+ 1 }  =  \sqrt{37}

The equation of the circle is given by:

(x-h)^2 + (y-k)^2 =  {r}^{2}

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

(x- - 1)^2 + (y-1)^2 =  {( \sqrt{37}) }^{2}

(x + 1)^2 + (y - 1)^2 = 37

We expand to get:

{x}^{2}  + 2x  + 1 +  {y}^{2}  - 2y + 1 = 37

{x}^{2}   +  {y}^{2} +  2x  - 2y +2 - 37= 0

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We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

{x}^{2}   +  {0}^{2} +  2x  - 2(0)  -   35= 0

{x}^{2}   +2x   -   35= 0

(x - 5)(x + 7) = 0

x = 5 \: or \: x =  - 7

The point (5,0) and (-7,0) lies on the circle.

When x=0

{0}^{2}   +  {y}^{2} +  2(0)  - 2y   -  35= 0

{y}^{2} - 2y   -  35= 0

(y - 7)(y + 5) = 0

y = 7 \: or \: y =  - 5

The point (0,-5) and (0,7) lie on this circle.

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Step-by-step explanation:

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Insert x for cos(x):

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Sorry if this is confusing.



6 0
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