Need more information on it to solve
Answer: Kobe made 25 shots.
Step-by-step explanation:
let 'x' be the number of shot made and 'y' be the number of shots missed.
Then according to the question, we have the following equation:-
Substitute the value of x from (1) in (2), we get
From(1), x=25
Hence, Kobe made 25 shots.
As is it tangent line
by using slope formula
y-y1 = m(x-x1)
given <span>a=pi/6=x1
</span>f(x)= sinx
above equation can be wriiten as
f(x)-f(a) = f’(a)(x – a)
so L(x)=f’(a) (x-a) + f(a)
f(x) = sinx =f(pi/6) =
1/2= y1
f’(x) = cosx f’(pi/6)=
3/2 = m
now putting values
L(x) = <span>√ </span>3/2( x-pi/6)+1/2
L(x) = (√ 3/2)x+6-pi√ <span>3/12</span>
Answer:
and 
Step-by-step explanation:
Given : 
To Find : Find the values of 
and 
where the following two constraints intersect.
Solution:
Plot these constraints on the graph
--- Red
--- Blue
The intersection point will provide the solution
So, Intersection point = (9.654,-4.269)
So, and
Refer the attached figure .
9514 1404 393
Answer:
56
Step-by-step explanation:
In the base-10 number system, the only two digits that have themselves as the least significant digit of their square are 5 and 6.* If multiplying a 2-digit number by the ones digit gives a ones-digit of 6, then the ones digit must be 6.
Similarly, if the ones digit of the product is 5, the ones digit of the number must be 5.
So, the ones digit of the original number is 6, and the ones digit of the reversed 2-digit number is 5. The original number is 56.
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<em>Check</em>
56 × 6 = 336
65 × 5 = 325
5 + 6 = 11
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<em>* Additional comment</em>
These digits are called "automorphs." Automorphs ending in 5 or 6 can be extended to any number of digits. For example, the 3-digit automorph ending in 6 is 376. <em>376</em>² = 141<em>376</em>. Similarly, the 3-digit automorph ending in 5 is 625. <em>625</em>² = 390<em>625</em>
