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11Alexandr11 [23.1K]
2 years ago
11

Write 7 × √7 as a single power of 7.

Mathematics
2 answers:
Natasha2012 [34]2 years ago
7 0

Answer:

{7}^{ \frac{3}{2} }

Step-by-step explanation:

\sqrt{7}  \: can \: also \: be \: written \: as \:  {7}^{ \frac{1}{2} }

We can use this information to rewrite the original expression:

7 \times  {7}^{ \frac{1}{2} }

7 can also be written as

{7}^{1}

Remember that when multiplying exponents, if they have the same base, we can add the exponents. Therefore:

{7}^{1}  \times  {7}^{ \frac{1}{2} }  \\  {7}^{1 +  \frac{1}{2} }  \\  {7}^{1 \frac{1}{2} }   \\  {7}^{ \frac{3}{2} }

maw [93]2 years ago
3 0

Answer:

7 x 2.6

Step-by-step explanation:

the square root of 7 is exactly 2.645751311064591, so in this case I converted it to a smaller number, using tenths place.

solution:

7 x 2.6 = 18.2

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Evaluate g (c) = 4 - 3x when c = -3, 0, and 5
Lana71 [14]

Answer:

6.09

Step-by-step explanation:

multiplayer ok so that is how I did it ok

6 0
2 years ago
Thanks for your response!<br> Question will be show✔
algol13
<h3>Answer:</h3>

\large\boxed{-1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}}

<h3>Step-by-step explanation:</h3>

In this question, it's asking you to put the numbers that were given from <em>least </em>to <em>greatest.</em>

Our given numbers are:

  • \frac{6}{40}
  • 0.35
  • 1\frac{3}{4}
  • -1\frac{16}{25}

Now, lets sort them out.

We know that negative numbers would be the least. Sicne there's only one negative number, we would put that first because it's the least out of the numbers.

\frac{6}{40} would go next. To make it easier, we can turn it into a decimal. \frac{6}{40} = 0.15 when you divide.

0.35 will go next. This would be bigger than 0.15, but lower than the next number.

1\frac{3}{4} would go last, due to the fact that it's the greatest. 1\frac{3}{4} is the same as 1.75

When you put them in order, you should get -1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
4 0
3 years ago
A circle with a radius equal to 12 feet.
inn [45]

Answer:

What do you mean a radius equal to 12 feet? What is your question?

Step-by-step explanation:

8 0
2 years ago
Define the double factorial of n, denoted n!!, as follows:n!!={1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n} if n is odd{2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n} if n is evenand (
tekilochka [14]

Answer:

Radius of convergence of power series is \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{1}{108}

Step-by-step explanation:

Given that:

n!! = 1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n        n is odd

n!! = 2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n       n is even

(-1)!! = 0!! = 1

We have to find the radius of convergence of power series:

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

Power series centered at x = a is:

\sum_{n=1}^{\infty}c_{n}(x-a)^{n}

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

a_{n}=[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}n!(3(n+1)+3)!(2(n+1))!!}{[(n+1+9)!]^{3}(4(n+1)+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]

Applying the ratio test:

\frac{a_{n}}{a_{n+1}}=\frac{[\frac{32^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]}{[\frac{32^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]}

\frac{a_{n}}{a_{n+1}}=\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

Applying n → ∞

\lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}= \lim_{n \to \infty}\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

The numerator as well denominator of \frac{a_{n}}{a_{n+1}} are polynomials of fifth degree with leading coefficients:

(1^{3})(4)(4)=16\\(32)(1)(3)(3)(3)(2)=1728\\ \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{16}{1728}=\frac{1}{108}

4 0
3 years ago
PLEASE HURRRYYY Simplify <br> √x2 (2 means squared)
Maslowich

Answer:

\sqrt{x ^{2} }  \\   { = ( {x}^{2} )}^{ \frac{1}{2} }  \\  =  {x}^{ \frac{2}{2} }   =  {x}^{1} \\  = { \boxed{ \boxed{x}}}

7 0
2 years ago
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