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11Alexandr11 [23.1K]
3 years ago
11

Write 7 × √7 as a single power of 7.

Mathematics
2 answers:
Natasha2012 [34]3 years ago
7 0

Answer:

{7}^{ \frac{3}{2} }

Step-by-step explanation:

\sqrt{7}  \: can \: also \: be \: written \: as \:  {7}^{ \frac{1}{2} }

We can use this information to rewrite the original expression:

7 \times  {7}^{ \frac{1}{2} }

7 can also be written as

{7}^{1}

Remember that when multiplying exponents, if they have the same base, we can add the exponents. Therefore:

{7}^{1}  \times  {7}^{ \frac{1}{2} }  \\  {7}^{1 +  \frac{1}{2} }  \\  {7}^{1 \frac{1}{2} }   \\  {7}^{ \frac{3}{2} }

maw [93]3 years ago
3 0

Answer:

7 x 2.6

Step-by-step explanation:

the square root of 7 is exactly 2.645751311064591, so in this case I converted it to a smaller number, using tenths place.

solution:

7 x 2.6 = 18.2

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8 months

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3 years ago
Solve for x. Enter the solutions from least to greatest.<br> 4x^2 + 40x + 84 = 0
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x= -3 , -7

Step-by-step explanation:

6 0
3 years ago
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WILL MARK YOU BRAINLIEST ANSWER WHAT YOU CAN PLS
maks197457 [2]

Answer:

1.

T mBAC = mB'A'C'

F 2mABC = mA'B'C'

F BC = 2B'C'

T 2XA = XA'

2

D'(-2/3; -1)

E'(-1;1)

F'(1;1)

G'(1;-1)

3

the centre is L(0;-2)

the scale factor is 4

length J'K' = 4JK

the measure of L is equal the measure of L'

<u>the</u><u> </u><u>table</u><u>:</u>

K(4;2) 4 4 16 16 0+16 -2+16 K'(16;14)

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3 years ago
What is sixteen ninths minus five Ninths in a number bound
kvv77 [185]

Answer:

i dont know what a number bound is but

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SOMEONE HELP ME WITH THIS PROOF
Pavlova-9 [17]
Okay, for this proof, I'll write the steps out.

Statements:
1. ABCD is a parallelogram
2. FG bisects DB
3. <GEB ≡ (pretend congruent symbol) <FED
4. DE ≡ BE
5. <CDA ≡ <ABC
6. < CDB ≡ <DBA
7. triangle DFE ≡ triangle BGE
8. FE ≡ GE
9. DB bisects FG

Reasons:
1. Given
2. Given
3. vertical angles are congruent
4. If bisected, then split into congruent parts
5. opposite angles of a parallelogram are congruent
6. Subtraction Property
7. ASA
8. CPCTC
9. segment split into congruent parts by other segment is bisected.

Hope this helped!  :)
6 0
3 years ago
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