<span>The answer is It represents a nonlinear function because its points are not on a straight line.</span>
Answer:
36
Step-by-step explanation:
The maximum height is the y-coordinate of the vertex
given a quadratic in standard form : ax² + bx + c : a ≠ 0
then the x-coordinate of the vertex is
= - 
y = - x² + 20x - 64 is in standard form
with a = - 1, b = 20 and c = - 64, hence
= - 
= 10
substitute x = 10 into the equation for y
y = - (10)² + 20(10) - 64 = 36 ← max height
To solve with Elimination:
Write the equations under one another, like this:
2x - y = -1
+ 3x + 4y = 26
Ideally, we would like for one of the variables to be eliminated when we add vertically (straight down). But if we add them as they are this does not happen. We must manipulate one of the equations so that it will happen. Again, you can try to eliminate either x or y. I always look for a term that has a coefficient of 1 (or negative 1). So, let's use that y from the first equation again.
If the coefficient of the y in the other equation is POSITIVE 4, then I need the coefficient from the first equation to be its opposite, NEGATIVE 4. To do this, simply multiply the first equation by 4, this will create MAGIC!
4( 2x - y = -1)
+ 3x + 4y = 26
Be certain to Distribute across the entire first equation, so multiply all three terms by 4.
8x - 4y = -4
+ 3x + 4y = 26
Now add straight down (vertically). The y term will be eliminated.
11x = 22
Divide both sides of the equation by 11.
x = 2
Almost there! Now, substitute the 2 in for x in either of the original equations. Either one will work. I'm gonna use the second equation.
3x + 4y = 26
3(2) + 4y = 26
6 + 4y = 26
Subtract 6 from both sides of the equation.
4y = 20
Divide both sides of the equation by 4.
y = 5
That's it! There it is again. Put it all together. If x = 2 and y = 5, then the solution is the ordered pair, (2,5).
I Think it would either be D or C
(I’m not sure, let me know if I’m wrong)
