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fiasKO [112]
4 years ago
7

Fill in the blank 31+____=61

Mathematics
2 answers:
eimsori [14]4 years ago
7 0
31+ ____ = 61
⇒ ____= 61 -31
⇒ ____= 30

The final answer is 30~
saveliy_v [14]4 years ago
6 0
31 plus 30 equals to 61
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The expression (3x^7)^4 is equivalent to c^n what is the value of c
Nimfa-mama [501]

Answer:

n= 21

c= 3x

Step-by-step explanation:

The expression is given as;

(3x⁷)⁴

Apply the brackets law of indices which states that :

If a term with a power is itself raised to a power then the powers are multiplied together

(xᵃ)ᵇ = xᵃˣᵇ

Applying the same;

(3x⁷)⁴ = 3x²¹

If 3x²¹ = c^n

Then n = 21

and

c= 3x

7 0
3 years ago
hi do I have this answer right? I just need someone help me out with this question so I can get the right answer
Kobotan [32]
I belive his answer is wrong B/c the graph does not even start near 310 the first to bars make it to 50 and 150 so even if u add the two together it would only be 200 so, the answer would be B
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3 years ago
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Serga [27]
Where is the map??????
8 0
3 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
There are 150 students in the sixth grade at Nimitz Middle School. Of these students, 12 students write left-handed. What percen
AlladinOne [14]

Answer:

nnnnnnnnnnnnnnnnnnnnnn

Step-by-step explanation:

jjjjjjjjjjjjjjjjjjjjjjjj

8 0
3 years ago
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