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3 years ago

12

In a right triangle, the side opposite angle has length 3.07 meters and the hypotenuse has length 7.89 meters. What is the sine

of the angle?

1 answer:

TiliK225 [7]3 years ago

5 0

Answer:

0.38910012674

Step-by-step explanation:

sine of the angle = (opposite angle has length) / ( hypotenuse has length )

sine of the angle = 3.07 / 7.89 = 0.38910012674

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Determine if<br> g(s) = 4s^2/3 <br> is even, odd, or neither.

madam [21]

$\star \ g(s) = \dfrac{4s^2}{3}$

$\star \ g(s) = 4* \dfrac{s^2}{3}$

$\star \ \dfrac{4s^2}{3}$

$\star = Odd$

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3 years ago

A graph has a constant of proportionality of 2.54. Let y represent centimeters and x represent inches. What is the unit rate of

Helga [31]

Answer: 2.54 is the rate of the given equation.

Step-by-step explanation:

Let x is the independent variable and y is the dependent variable.

Since, By the definition of proportionality,

y = k x

Where k is the constant of proportionality.

And, Here k = 2.54

Thus, the equation of line is,

y = 2.54 x

since, rate of the equation is the slope of the line.

And, the general equation of line

y = m x +c

Where, m is the slope of the line.

By comparing the equation of line y = 2.54 x with this.

The slope of the line = 2.54

Therefore, 2.54 is the rate of the given equation.

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3 years ago

Will mark brainlist and rate 5/5

erastova [34]

Sir you don’t even have a question

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3 years ago

Factor completely 6x^2-7x-3

hichkok12 [17]

$x = \frac{-(-7) +/- \sqrt{(-7)^{2}-4(6)(-3) } }{2(6)}$
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3 years ago

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

$2x^2-12x+20=0$

Simplifying by 2

$x^2-6x+10=0$

Completing squares

$x^2-6x+9+10-9=0$

Factoring and rearranging

$(x-3)^2=-1$

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

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3 years ago