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HACTEHA [7]
3 years ago
14

How do you solve (x3 + 6x2 + 3x + 1 ) ÷ (x - 2)

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0
We conduct long division, cancelling each term in x³ + 6x² + 3x + 1. As so:

x²(x -2) = x³ - 2x²
Subtracting from the original equation, we get:
8x² + 3x + 1

8x(x - 2) = 8x² - 16x
Subtracting from the new equation, we get:
21x + 1

21(x - 2) = 21x - 42
Subtracting from the new equation, we get:
43

The answer is x² + 8x + 21 with a remainder of 43.
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Solve the equation 40 = -10(y+0.3). what does the y equal​
alexdok [17]

Answer:

y = -4.3

Step-by-step explanation:

40 = -10(y + 0.3) <em>{Step 1: Use the distributive property to multiply -10 by y + 0.3}</em>

40 = -10y + -10(0.3)

40 = -10y - 3 <em>{Step 2: Add 3 to both sides.}</em>

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4 0
3 years ago
Read 2 more answers
What is the value of x if 5x+2 = 59?
lana66690 [7]

Answer:

x = 57/5 = 11.400

Step-by-step explanation:

Step  1  :

Solving a Single Variable Equation :

1.1      Solve  :    5x-57 = 0

Add  57  to both sides of the equation :

                     5x = 57

Divide both sides of the equation by 5:

                    x = 57/5 = 11.400

One solution was found :

                  x = 57/5 = 11.400

Processing ends successfully

plz mark me as brainliest :)

8 0
3 years ago
Read 2 more answers
11b-12&lt;-100
ruslelena [56]

Answer:

ok wait which symbol? this (<)?

well it should stay the same since -100 is greater than the 11b-12

LHS=RHS

11b÷11b b must cancell b also do the same on -12. -12÷11 will give u a lesser value compared to -100

prove me wrong

4 0
3 years ago
Read 2 more answers
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