If you do in fact mean 
(as opposed to one of these being the derivative of 
at some point), then integrating twice gives
From the initial conditions, we find
Eliminating 
, we get
![C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)](https://tex.z-dn.net/?f=C_1%20%3D%20-%5Cdfrac%7B%5Cln%286%29%7D5%20%3D%20-%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%20%5Cimplies%20C_2%20%3D%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29)
Then
![\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%20%3D%20%5Cln%7Cx%7C%20-%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%5C%2Cx%20%2B%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%7D)
A² + b² = c²
3² + 6² = x²
x² = 9 + 36
x² = 45
x = √45
x = 3√5
Answer: x = 3√5
For the Swiss cheese he sold 3 pounds of them and for the Cheddar cheese he sold 4 of them. When you multiply them together you get 24 for them both. 24+24=48. That's how you get your answer.
Let me tell you....
This equation cannot be solved at all.
Why?
3(n+5)≥3n+8
3n+15 ≥ 3n+8
3n-3n ≥ 8-15
0 ≥ -7
Even though it make sense than 0 ≥ -7... But since 'n' disappeared, this means that this equation have no solution. To solve means to find the value of 'n' and if there is no 'n' since 3n-3n=0, there is no solutions.
This question is pretty much invalid.
Extra:
To tackle such inequality qns:
Step 1: Expand the brackets
Step 2: Move the term to one side of the equations
and constant to another side of the equation.
Step 3: Find the value of the term. Done.
>Look at the question carefully and revise it or you can easily just....
Circle the main numbers!
Underline the question!
Break down the steps!
Elaborate the problem!
