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Nina [5.8K]
3 years ago
6

Find the distance (8,-7) (-4,-2)

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0

Distance = 13 units

Point A: (8, -7)

Point B: (-4, -2)

\sqrt{(8 + 4)^{2} + (-7 + 2)^{2} }

\sqrt{(12)^{2} + (-5)^{2} }

\sqrt{144 + 25 }

\sqrt{169}

13

kaheart [24]3 years ago
6 0

Answer:

\boxed {d = 13}

Step-by-step explanation:

Use the <u>Distance Formula</u> to help you find the distance between the two following points:

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}

(where (x_{1}, y_{1}) represents the first point and (x_{2}, y_{2}) represents the second point)

-Apply the two following onto the formula:

(x_{1}, y_{1}) = (8, -7)

(x_{2}, y_{2}) = (-4, -2)

d = \sqrt{(-4 - 8)^{2} + (-2 + 7)^{2}}

-Solve for the distance:

d = \sqrt{(-4 - 8)^{2} + (-2 + 7)^{2}}

d = \sqrt{(-12)^{2} + 5^{2}}

d = \sqrt{144 + 25}

d = \sqrt{169}

\boxed {d = 13}

Therefore, the distance is 13.

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The length of a rectangle is 4
Juli2301 [7.4K]

Answer:

w=16, L=20

Step-by-step explanation:Length(L)=w+4

P=72

P=2L+2w

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4 0
3 years ago
Add 1/4 + 5/14 +6/7 Simplify the answer and write it as a mixed number.​
zhannawk [14.2K]

Answer:

\frac{41}{28} = 1\frac{13}{28}

Step-by-step explanation:

In order to add fractions, the denominators must all be the same value (the lowest common denominator). The <em>lowest common denominator</em> is the smallest value that all of the given denominators (in this case, the denominators are 4, 14, and 7) can divide into.

Here, the smallest number that all three of the given denominators can perfectly divide into is 28:

28 ÷ 4 = 7

28 ÷ 14 = 2

28 ÷ 7 = 4

<em>Therefore, our lowest common denominator is 28.</em>

<em />

The next step is to change our numerators to match our lowest common denominator. To do this, we have to multiply the numerator by the same value that we would need to multiple the denominator by in order to get our lowest common denominator.

For our first term of 1/4, we need to multiply our denominator (4) by 7 in order to get our lowest common denominator of 28. So, we need to also multiply our numerator by 7:

\frac{1}{4} × \frac{7}{7} = \frac{7}{28}

<em>Therefore, our first term becomes </em>\frac{7}{28}<em>.</em>

For our second term of 5/14, we need to multiply our denominator (14) by 2. So, we need to also multiply our numerator by 2:

\frac{5}{14} × \frac{2}{2} = \frac{10}{28}

<em>Therefore, our second term becomes </em>\frac{10}{28}<em>.</em>

For our third term of 6/7, we need to multiply our denominator (7) by 4. So, we need to also multiply our numerator by 4:

\frac{6}{7} × \frac{4}{4} = \frac{24}{28}

<em>Therefore, our third term becomes </em>\frac{24}{28}<em>.</em>

Now that they all have the same denominator, we simply have to add all three together:

\frac{7}{28} + \frac{10}{28}<em> </em>+<em> </em>\frac{24}{28}<em> </em>= \frac{41}{28}

When we simplify this into a mixed number, we get:

\frac{41}{28} = 1\frac{13}{28}

<em />

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3 years ago
Read 2 more answers
Find x when : 3x^3 - 2x +1 = 0
notsponge [240]
Answer:  x = "-1 " ;  <u>and</u>:  "(1 ± √3) / 2" .
____________________________________________
Explanation:
____________________________________________
Given:  3x³ −  2x  + 1 = 0 ;  Find "x" ; 

Factor:  "3x³ −  2x + 1"  ;

3x³ − 2x + 1 = (3x² <span>− 3x + 1)(x + 1) ;

Now, set the equation equal to "0" (zero);

</span> (3x² − 3x + 1)(x + 1) = 0 ;

x = 0  ; when:
__________________________________
(x + 1) = 0 ;  and/or: when:

(3x² − 3x + 1) = 0 ;
__________________________________

Start with "x + 1 = 0" ;

Subtract "1" from each side of the equation ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ; 

              x + 1 − 1 = 0 − 1 ; 

                x = -1 ;

_______________________________
Now, try:  

3x² − 3x + 1 = 0 ;

Since:  "3x² − 3x + 1 " cannot be factored; and since:

  "3x² − 3x + 1 = 0" ; is written in the "quadratic equation format"; that is:

  "ax² + bx + c = 0 ;  a ≠ 0;  We can use the "quadratic equation formula" to solve for "x" ;  

in which "a = 3" ;   
              "b = -3" ;
              "c = 1" ;
     
The quadratic equation formula is:
__________________________________

x = [-b ± √(b²−4ac] / 2a ;

   = ?  (Let us plug in our known values for "a, b, & c"l 

x = { [-(-3] ± [√[(-3²) − (4*3*1)] } / {2* 3} ;

x = [3 ± √(9 − 12)] / 6 

x = [3 ± √(-3 )] / 6 ; 

x = (1 ± √3) / 2 .
<span>__________________________________________________
So, the answers are:  x = " -1 " ;  and:  "</span>(1 ± √3) / 2 " .
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8 0
3 years ago
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