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Nina [5.8K]
3 years ago
6

Find the distance (8,-7) (-4,-2)

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0

Distance = 13 units

Point A: (8, -7)

Point B: (-4, -2)

\sqrt{(8 + 4)^{2} + (-7 + 2)^{2} }

\sqrt{(12)^{2} + (-5)^{2} }

\sqrt{144 + 25 }

\sqrt{169}

13

kaheart [24]3 years ago
6 0

Answer:

\boxed {d = 13}

Step-by-step explanation:

Use the <u>Distance Formula</u> to help you find the distance between the two following points:

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}

(where (x_{1}, y_{1}) represents the first point and (x_{2}, y_{2}) represents the second point)

-Apply the two following onto the formula:

(x_{1}, y_{1}) = (8, -7)

(x_{2}, y_{2}) = (-4, -2)

d = \sqrt{(-4 - 8)^{2} + (-2 + 7)^{2}}

-Solve for the distance:

d = \sqrt{(-4 - 8)^{2} + (-2 + 7)^{2}}

d = \sqrt{(-12)^{2} + 5^{2}}

d = \sqrt{144 + 25}

d = \sqrt{169}

\boxed {d = 13}

Therefore, the distance is 13.

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With a slope of m = -2 and a point being (5,-2) what’s the Y-intercept?
almond37 [142]

Answer:

c = 8

Step-by-step explanation:

Given the following data;

Slope, m = -2

Points (x, y) = (5, -2)

To find the intercept, c;

Equation of a straight line is given by the formula: y = mx + c

Where;

m is the slope.

x and y are the points

c is the intercept.

Substituting the values in order to find the intercept, we have;

-2 = -2(5) + c

-2 = -10 + c

c = 10 - 2

c = 8

Therefore, the y-intercept is 8.

3 0
3 years ago
Find the point P on the line y=2x that is closest to the point (20,0) .what is the least distance between pans (20,0)?
Vsevolod [243]
The closest point on a line, to another point, will be a point that's on a normal of that line, or a line that is perpendicular to it, notice picture below

so, y = 2x, has a slope of 2, a perpendicular line to it, will have a slope of negative reciprocal that, or \bf 2\qquad negative\implies -2\qquad reciprocal\implies \cfrac{1}{-2}\implies -\cfrac{1}{2}

so, we know that line passes through the point 20,0, and has a slope of -1/2

if we plug that in the point-slope form, we get \bf y-0=-\cfrac{1}{2}(x-20)\implies y=-\cfrac{1}{2}x+10

now, the point that's on 2x and is also on that perpendicular line, is the closest to 20,0 from 2x, thus, is where both graphs intersect, as you can see in the graph

thus  \bf 2x=-\cfrac{1}{2}x+10  solve for "x'

------------------------------------------------------------

not sure on the 2nd part, but sounds like, what's the distance from that point to 20,0, well, if that's the case, just use the distance equation

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ \square }}\quad ,&{{ \square }})\quad &#10;%  (c,d)&#10;&({{ \square }}\quad ,&{{ \square }})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}


6 0
3 years ago
Very very very long essay on the topic of mom​
Leokris [45]
For 5 points? Good luck getting someone to do that for you
4 0
2 years ago
Helppppppppppppppp lol
Sladkaya [172]
The given expression is: 
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Let's look at each terms separately:
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Combining both, you can conclude that you are adding 5 to half a certain given number.

Comparing this with the choices, the correct choice would be:
C. five more than half a number.

5 0
3 years ago
Read 2 more answers
This is worth 20 points
Ann [662]
45 minutes because it has 4 dots and that’s greater than the rest on the dot plot.
7 0
3 years ago
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