Find the distance (8,-7) (-4,-2)
2 answers:
Distance = 13 units
Point A: (8, -7)
Point B: (-4, -2)





Answer:

Step-by-step explanation:
Use the <u>Distance Formula</u> to help you find the distance between the two following points:

(where
represents the first point and
represents the second point)
-Apply the two following onto the formula:



-Solve for the distance:





Therefore, the distance is
.
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