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Cloud [144]
3 years ago
6

i'm giving brainiest right now so first one who has correct gets brainiest!!The length of one side of a square pond is 15 feet.

The pond is surrounded by a 3 foot wide walkway. What is the total area of the pond and the walkway, in square feet?
Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0
It’s easiest to think about it this way:

If the pond is 15 feet wide, then adding 3 feet to each side would increase the side length to the square by six feet (3 feet on each side). This makes the area within the square equal to 18x18 feet, or 324 square feet. But, this isn’t the area of the sidewalk, it’s the area of the sidewalk plus the area of the pool.

The pool is fifteen feet wide, which means that it has an area of 225 square feet. So, to find the area of the side walk, we can subtract the area of the pool from the area of the pool and sidewalk, which will give us the area of the sidewalk by itself.

324-225=99 square feet.

The pool has an area of 225 square feet, and the sidewalk has an area of 99 feet.
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X-y=5 and x^2y=5x+6​
sergeinik [125]

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

<h3>How to solve a system of equations</h3>

In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

To learn more on nonlinear equations: brainly.com/question/20242917

#SPJ1

8 0
1 year ago
1. This composite figure is created by placing a sector of a circle on a rectangle. What is the area of this composite figure? S
White raven [17]

Answer:

29.92 m² (nearest hundredth)

Step-by-step explanation:

\textsf{Area of a sector}=\dfrac{\theta}{360\textdegree}\pi r^2

\implies \textsf{area}=\dfrac{30}{360\textdegree}\pi \cdot 5.5^2=\dfrac{121}{48}\pi \textsf{  m}^2

Area of rectangle = width × length

⇒ area = 4 × 5.5 = 22 m²

Total area = area of sector + area of rectangle

⇒ total area = \dfrac{121}{48}\pi +22 = 29.91943148... = 29.92 m² (nearest hundredth)

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2 years ago
Chance can wash the car in 2 hours, while Sandy can wash the same car in 4 hours. How many hours would it take for them to wash
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<span>1 hour and 1/3rd of an hour
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so A is right 
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