Answer:
(a) f'(1)=-4
(b) y+4x-4=0
Step-by-step explanation:
<u>Tangent Line of a Function</u>
Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.
We are given
The derivative is
(a) The slope of the tangent line at (1,0) is
(b) The equation of the tangent line can be found with the general formula of the line:
Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus
Or, equivalently
Step-by-step explanation:
4x²-9
4x²+6x-6x-9
4x²+6x-6x-9
2x(2x+3)-3(2x+3)
2x(2x+3)-3(2x+3)
(2-3)(2x+3)
solution
(8x-3)(2x+3)
The y intercept of this function is always (0, a).
This is because when we place 0 in for x (which is the only way it'll be on the y-axis, we get 'a' as a result. This is because of the rule that raising anything to the 0th power will result in the number 1 and multiplying anything by 1 gives us the same number. See the work below for the example.
F(x) = a*b^x
F(0) = a*b^0
F(0) = a*1
F(0) = a
And for an example with a random number, we'll use a = 5 and b = 3
F(x) = 5*3^x
F(0) = 5*3^0
F(0) = 5*1
F(0) = 5
No matter what a and b equal, the intercept will be the a value.
K is constant. if you increase g(x) by x. f(x) also increases by x
Answer:
Move the top side down 2 meters
