Hi there,
your question is asking for the angle of the central circle, and the formula is: the two arcs' sum divided by 2
So,
(60 + 40) ÷ 2 = 50
The answer is 50°
Hope I helped :p
Answer:
n = -8
Step-by-step explanation:
![- 5n - 2 = 38](https://tex.z-dn.net/?f=-%205n%20-%202%20%3D%2038)
Collect like terms and simplify
![-5n = 38+2\\\\-5n = 40](https://tex.z-dn.net/?f=-5n%20%3D%2038%2B2%5C%5C%5C%5C-5n%20%3D%2040)
Divide both sides of the equation by -5
![\frac{-5n}{-5n} = \frac{40}{-5}](https://tex.z-dn.net/?f=%5Cfrac%7B-5n%7D%7B-5n%7D%20%3D%20%5Cfrac%7B40%7D%7B-5%7D)
Simplify
![n = -8](https://tex.z-dn.net/?f=n%20%3D%20-8)
1. Let the sides of a triangle be a, b and c.
Assume c is the largest side.
The maximum angle measure in an acute triangle can be 90°. In such a case we would have
![a^{2} + b^{2} = c^{2}](https://tex.z-dn.net/?f=%20a%5E%7B2%7D%20%2B%20b%5E%7B2%7D%20%3D%20c%5E%7B2%7D%20)
Now forget about side c, and open the angle between a and b just a little bit. Now clearly
![a^{2} + b^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2B%20b%5E%7B2%7D)
is larger that
![c^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D)
because the "new c" is larger than the old one.
2. So for 3 numbers to be the lengths of the sides of an acute triangle, the sum of the squares of the 2 smaller numbers must be at most equal to the square of the largest number but not more.
Check:
A. 4^2+5^2=16+25=41<49
B. 5^2+7^2=25+49=74>64
C. 6^2+7^2=36+49=85<100
D. 7^2+9^2=49+81=130<144
3. Correct answer: only B
Hi there! Okay, so the bases are 60 feet apart. From home base to first plate, you would travel 60 feet and from first plate to second plate, you travel another 60 feet. 60 + 60 is 120. Home plate is 120 feet away from second base.