<h3>3
Answers: Choice C, Choice D, Choice F</h3>
What these expressions have in common is that their exponents multiply to 16
- (-4)*(-4) = 16 for choice C
- (-2)*(-8) = 16 for choice D
- 8*2 = 16 for choice F
The rule used here is (a^b)^c = a^(b*c). We multiply the exponents and keep the base the same.
Answer:
4V-32
If is was wrong then don't report on me just tell me and I will automatic fix it for you
<em>Answer:</em>
<em>D)</em>
<em>Step-by-step explanation:</em>
<em>We know that it cannot be C since z is not involved in this problem.</em>
<em>a) 3/20x</em>
<em>Try with 20 = x</em>
<em>3/440 ≠ 3</em>
<em>A is not the answer.</em>
<em>b) 60x</em>
<em>Try with 20 = x</em>
<em>1800 ≠ 3</em>
<em>B is not the answer.</em>
<em>c) 60/x</em>
<em>Try with 20 = x</em>
<em>3 = 3</em>
<em>Try with 15 = x</em>
<em>4 = 4</em>
<em>D is your answer.</em>
<em>Hope this helps. Have a nice day. Oh, and one more thing. Surprised to see I'm not stealing points?</em>
Given data
1. The mean
2. The median
3. The sample standard deviation
![\begin{gathered} SD\text{ =}\sqrt[]{\frac{\sum f|x-\bar{x}|}{\sum f}} \\ \bar{x}=7.6515 \\ SD=\sqrt[]{4.8028} \\ SD=2.1915 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20SD%5Ctext%7B%20%3D%7D%5Csqrt%5B%5D%7B%5Cfrac%7B%5Csum%20f%7Cx-%5Cbar%7Bx%7D%7C%7D%7B%5Csum%20f%7D%7D%20%5C%5C%20%5Cbar%7Bx%7D%3D7.6515%20%5C%5C%20SD%3D%5Csqrt%5B%5D%7B4.8028%7D%20%5C%5C%20SD%3D2.1915%20%5Cend%7Bgathered%7D)
Answer:
313,600
Step-by-step explanation:
Let t represent number of years after Beth's 9th birthday.
We have been given that since Beth was born the population of her towns has increased at a rate of 850 people per year. So number of people increased in t years would be 
.
We are also told that on Beth's 9th birthday the total population was nearly 307,650. This means that t-intercept is 307,650.
The population of town t years after Beth's birthday would be 
.
To find population on Beth's 16th birthday, we will substitute 
in our equation as Beth's 16th birthday would be 7 years after 9th birthday.
Therefore, the population on Beth's 16th birthday would be 313,600.
