Answer: 6.403 miles; or, write as: 6.403 mi. .
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Explanation:
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5
--------------------------------------------
` right angle |_ |
` (right triangle ) |
` | 4
` |
`
"c" ` \
(hypotenuse) Starting point
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Since we have a "right triangle, we solve for "c"; using the
"Pythagorean theorem" ;
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→ a² + b² = c² ; Solve for "c" ; our answer (in "miles"; or, "mi.") ;
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Given : a = 4; b = 5 ;
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Plug these known values into our equation:
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→ 4² + 5² = c² ;
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→ 16 + 25 = c² ; ↔ c² = 16 + 25 ;
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→ c² = 41 ;
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→ Take the positive square root of each side of the equation (since the side of a "triangle" cannot be "negative";
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→ √(c²) = √(41) ;
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→ c = √41 ; Use calculator;
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→ c = 6.40312423743 ; Round to:
→ c = 6.403 miles; or, 6.403 mi.
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Factors of 32-
1*32
2*16
4*8
1, 2, 4, 8, 16, and 32 are factors of 32 (Their multiples are 32)
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
- 5
- 6
- 6
- 5
Remember the decimal <em>hundredths</em> rounding ruleset.
- If a decimal is below .50, round down.
- If a decimal is .50, round up.
- If a decimal is above .50, round up.
View this array below to get a better image.
![\left[\begin{array}{ccc}0.49(down)&0.50(up)&0.51(up)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.49%28down%29%260.50%28up%29%260.51%28up%29%5Cend%7Barray%7D%5Cright%5D)
So, for example, if you had 6.51, you would round that up to 7, and if you had 8.47, you would round that to 8
