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2 years ago

What are the solution(s) to the quadratic equation x2 – 25 = 0?

Mathematics

2 answers:

DIA [1.3K]2 years ago

7 0

X= 5 and it also equals -5

yanalaym [24]2 years ago

4 0

x²-25 = (x+5) ( x-5)

As a multiplication can only add up to zero if one of term is 0 ,

there is two solutions :

x+5 = 0

x = -5

and x-5 = 0

x = 5

So two solutions for x² -25 = 0 which are -5 and 5

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5 0

3 years ago

The answer and the work that was needed to solve it .

cupoosta [38]

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7 0

3 years ago

Read 2 more answers

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Elenna [48]

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A) 10.00

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6 0

1 year ago

Subtract (5x^2-5) from the sum (x^2-9x+2) and (4x^2-5x+1)

Ivan

Assignment: $\bold{Solve \ Equation: \ \left(x^2-9x+2\right)+\left(4x^2-5x+1\right)-\left(5x^2-5\right)}$

<><><><><><><>

Answer: $\boxed{\bold{-14x+8}}$

<><><><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><><><>

[ Step One ] Remove Parenthesis: (a) = a

$\bold{x^2-9x+2+4x^2-5x+1-\left(5x^2-5\right)}$

[ Step Two ] Simplify $\bold{-\left(5x^2-5\right)}$

$\bold{-5x^2+5}$

[ Step Three ] Rewrite Equation

$\bold{x^2-9x+2+4x^2-5x+1-5x^2+5}$

[ Step Four ] Simplify $\bold{x^2-9x+2+4x^2-5x+1-5x^2+5}$

$\bold{-14x+8}$

<><><><><><><>

$\bold{\rightarrow Mordancy \leftarrow}$

3 0

3 years ago

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lesantik [10]

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5 0

2 years ago