6. One variable only so pretty straightforward.
length-x+4
width-x
x+x+4=80
2x=76
x=38
x+4=42
answer: length 42cm and width 38cm
7. Another money problem!
n-# of nickels
q-# of quarters
n=3+q
0.05n+0.25q=2.85
Substitution works like a charm!
0.05(3+q)+0.25q=2.85
0.15+0.05q+0.25q=2.85
0.3q=2.7
q=9
n=3+q
n=3+9
n=12
answer: 9 nickels and 12 quarters
8. One variable situation again.
Ann's money-2b+9
Betty's money-b
b+2b+9=60
3b=51
b=17
2b+9=43
answer: Ann has $43 and Betty has $17.
9. # of red m&m's-x+1
# of blue m&m's-x
x+1+x=13
x=6
x+1=7
answer: 6 blue and 7 red m&m's
10. a-number of adult tickets
s-number of student tickets
a+s=785 ----> a=785-s
5a+2s=3280
5(785-s)+2s=3280
-3s=-645
s=215
a+s=785
a+215=785
a=570
answer: 215 children tickets and 570 adult tickets
9. You shouldn't agree, because they are equal to one another.
10. 84 cents plus 61 should be $1.45 because 84 + 61 is 145 and 100 cents equals 1 dollar, and then you have 45 left over.
100 - .63 is .37 because the whole painting is equal to 1, or .1, or in this case I used it as 100. The drawing is up to you, but you can just draw a canvas and shade in a little bit more than half but not the full canvas. .37 of the canvas is left.
Answer:
False
Step-by-step explanation:
Range is defined as the greatest possible number minus the lowest possible number. The highest is 150 (in thousands) and the lowest is 25, meaning the range would be 125,000 and not 150,000.
Hope this helps!
