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Over [174]
3 years ago
8

Previous studies on sleep tendencies report that, on average, an adult American will sleep for 6 hours each night with a standar

d deviation of 0.75 hours. You survey a SRS of 100 adult Americans and determine that the mean sleep time is 5 hours. Which Hypothesis Test should be used here?
a. One-sample t-test for means.
b. One-sample z-test for means.
c. One sample z-test for proportions.
d. One sample t-test for proportions.
e. Chi-squared goodness of fit test.
Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Answer:

b) One sample z-test for means

Step-by-step explanation:

Normal Distribution

we have μ₀ (population mean from previous studies)

sample size    n  =  100

standar deviation of population   σ  = 0.75

And it was determined from sample, that μ = 5 : so we want to know if, at some significance level that value (which is smaller than population mean ) could help in relation to decide about rejecting hypothesis  H₀

We should use a z one tail-test for means (left tail)

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______________________________________________________
Area of a circle, "A" :  A = π * r² ;

  in which: A = Area of circle ;
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radius of a circle, "r" = d / 2  ;  in which:  "d = diameter" ;

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3 0
3 years ago
Kirk's family drove 36 miles in 50 minutes, which was 48% of the distance to his grandmother's house. What was the total distanc
Makovka662 [10]

Answer:

Option D is correct.

75 miles is the total distance in miles to Kirk's grandmother's house

Step-by-step explanation:

Let x represents the total distance in miles to Kirk's grandmother's house.

As per the statement:

Kirk's family drove 36 miles in 50 minutes, which was 48% of the distance to his grandmother's house

⇒ Distance Kirk's family drove = 36 miles.

then;

36 = 48% of x

36 = \frac{48}{100}x

Multiply both sides by 100 we get;

3600 = 48x

Divide both sides by 48 we have;

75 miles = x

Therefore, the total distance in miles to Kirk's grandmother's house is 75 miles

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