P= (2)(x-2)+(2)(5)
P= (x-2)+(x-2)+5+5
First you must have the quadratic equal to zero. In order to do this you must subtract 7 to both sides
x^2 + 20x + (100 - 7) = 7 - 7
x^2 + 20x + 93 = 0
Now you must find two numbers who's sum equals 20 and their multiplication equal 93
Are there any? NO!
This means that you have to use the formula:

In this case:
a = 1
b = 20
c = 93



^^^We must simplify √28
√28 = 2√7
so...

simplify further:

-10 + √7
or
-10 - √7
***plus/minus = ±
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer:
the answer is 83 because 5+3=8 and 3+0=3
F(x) = x^2 + 1 f(10)
f(10) = 10^2 + 1
f= 101
i am sorry i was gonna anwer but i keep getting it wrong mys elf