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Masteriza [31]
3 years ago
14

HELP ASAP!! the graph is in the picture above to reference it!!

Mathematics
2 answers:
Nikitich [7]3 years ago
8 0
I believe it is B and C. (Side note, I got the same computer from K-12 lol I’m in 8th grade and this is my first year, will it get easier?!?)
jenyasd209 [6]3 years ago
5 0

Answer: There are two correct statements, which are:

b. the intersection (1,60) indicates the time in hours when celia and tayvin are the same distance from the city.

c. Celia drove at a faster rate than Tayvin.


Explanation:

The graph shows two linear functions with these characteristics and informations:

  • dependent variable (vertical axis): distance traveled in miles)
  • independent variable (horizontal axis): time (hours):
  • Tayvin's function:

         - inicial distance = y-intercept: (0,10) = 10 miles

         - speed = slope = rise / run = [ 60 miles - 50 miles ] / [ 1 hour] =

            speed = 50 miles / hour            

  • Celia's function:

        - initial distance = y-intercept: (0,0) = 0

        - speed = slope = rise / run = [60 miles - 0 miles]  / [ 1 hour] =

           = speed = 60 miles / hour

         

With that you can go over each answer choice to asses their validity:


a. Tayvin drove a faster rate than Celia.

    FALSE. It was shown that Tayvin's speed was 50 miles/hour while Celia's speed was 60 miles/hour, hence Celia was 10 miles/hour faster than Tayvin.


b. the intersection (1,60) indicates the time in hours when Celia and Tayvin are the same distance from the city.

  TRUE. The two lines intersect each other at the point with coordinates (1,60), where 1 is the time in hours and 60 is the distance in miles, meaning that both were at the same distance (60 miles) at the same time (1 hour).


c. Celia drove at a faster rate than Tayvin.

  TRUE. As stated before, Celia drove 10 miles/hour faster than Tayvin


d. the intersection (1,60) indicates the time in hours when celia and tayvin are traveling at the same speed.

    FALSE. As stated in the point b., the intersection point  indicates the time in hours when Celia and Tayvin are the same distance from the city; the speed were different all the time, since both kept thier respective uniform speeds (constant slope means constant speed).


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What is the solution of the system of equations below?
8090 [49]

G

Solution:

Here,

y+2x=2

y=2-2x

Now,

Putting the value of y

y+4x=0

2-2x+4x=0

2+2x=0

2(1+x)=0

1+x=0

x=-1

Then,

Putting the value of x

y=2x-2

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Hence,the solution is (-1,-4)

8 0
3 years ago
Please help me, due tomorrow!
Ierofanga [76]

Answer:

x=12

Step-by-step explanation:

3x-4=2x+8

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x =12

5 0
3 years ago
Please help me on this question (answer all parts please)
ozzi

SOLUTION:

Case: Volume of Sphere

Method:

a) The volume of a sphere whose diameter, d= 28in

The radius,

r= 28/2

r= 14 in

The Volume, therefore:

\begin{gathered} V=\frac{4}{3}\pi r^3 \\ V=\frac{4}{3}\pi\times14\times14\times14 \\ V=11494.04\text{ }cubic\text{ }inches \end{gathered}

b) When half of the volume is used,

\begin{gathered} V=\frac{1}{2}V_0 \\ V=\frac{1}{2}\times11494.04 \\ V=5747.02\text{ }cubic\text{ }inches \end{gathered}

c) The radius of the halved volume

\begin{gathered} V=\frac{4}{3}\pi r^3 \\ 5747.02=\frac{4}{3}\pi r^3 \\ r^3=\frac{3\times5747.02}{4\pi} \\ r^3=1372 \\ r=\sqrt[3]{1372} \\ r=11.11\text{ }inches \end{gathered}

Final answer: (To 2 d.p)

a) 11494.04 cubic inches

b) 5747.02 cubic inches

c) 11.11 inches

5 0
2 years ago
If M is the midpoint of segment AB, then which of the following statements is/are true? AB=MB AM=MB Segment AM is congruent to s
Archy [21]

AB is the large segment.

AM is half of the large segment.

MB is the second half of the large segment.

AM = MB is true.

Segment AM is congruent to segment MB is true.

AB = MB is false.

3 0
4 years ago
A production supervisor at a major chemical company wishes to determine whether a new catalyst, catalyst XA-100, increases the m
zheka24 [161]

Answer:

a. n= 47

b. n= 128

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.

You need to calculate the sample size to estimate the population with determined error margins.

To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.

The formula of the margin of error (d) is:

d= t_{n-1: 1-\alpha/2} * (\frac{S}{\sqrt{n} })

I've  cleared the sample size of the formula

n= (S*\frac{t_{n-1; 1-\alpha /2} }{d} )^{2}

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.

a)

95% CI

d= 8 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.025}  = t_{4;0.975} =2.776

n= (19.62*\frac{2.776 }{8} )^{2}

n= 46.35 ≅ 47

b)

99% CI

d= 5 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.005}  = t_{4;0.995} =4.604

n= (19.62*\frac{4.604}{8} )^{2}

n= 127.49 ≅ 128

I hope it helps!

4 0
3 years ago
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