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Marizza181 [45]
3 years ago
13

The width of a rectangle is 33cm. The perimeter is at least 776 centimeters. Hat would the inequality be?

Mathematics
1 answer:
inessss [21]3 years ago
7 0
So, I'm assuming you need to find the inequality of the length of the rectangle. So, since we know the perimeter of a rectangle is:
P = 2(l+w)

And you are given the w (width), and also given that the perimeter's at least 776cm:
772 \geq 2(33+l)

We just solve for l:
772 \geq 66+2l
706 \geq 2l
\frac{706}{2} \geq l
353 \geq l

So your answer is:
l  \leq 353


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Convert the angle 0=17pi over 18 radians to degree
Shalnov [3]

Answer:

170°

Step-by-step explanation:

To convert from radians to degrees

degree measure = radian measure × \frac{180}{\pi } , thus

degree = \frac{17\pi }{18} × \frac{180}{\pi }

Cancel π on numerator/denominator and 18/ 180 by 18

degree measure = = 17 × 10 = 170°

8 0
3 years ago
Given b(x) - 1X+4. what is b(-10)? <br> -10<br> -6<br> 6<br> 14
liraira [26]

Answer:

D. 1×10⁻⁸ M

Explanation:

[H⁺] [OH⁻] = 10⁻¹⁴

(1×10⁻⁶) [OH⁻] = 10⁻¹⁴

[OH⁻] = 1×10⁻⁸

5 0
2 years ago
Read 2 more answers
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
What's 16 over 8 in a mixed number
olya-2409 [2.1K]
16/8= 2
2 is a whole number
4 0
3 years ago
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In the triangle below, the value of h is 3/4 the side length that is labeled on the figure. What is the area of the triangle?
Nataly_w [17]
The correct answer is:  [C]:  " 8.64 mm² " .
________________________________________________
Note: 
______________________________________________________
Area of a triangle = (½)*(base length)*(height; that is, "perpendicular height");
________________________________________________________
or:  A = (½) * b * h ;
_________________________
Given:  "b = 4.8 mm" ;
            "h = (¾) * b = (¾)* (4.8 mm) = 3.6 mm ;
               → h = 3.6 mm ;
_____________________________________
  →  A = (½) * b * h  ;

           = (½) * (4.8 mm) * (3.6 mm) ;

    →  A  =  8.64 mm² ; which is:  Answer choice: [C] .
______________________________________
4 0
2 years ago
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