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3 years ago

8

The african bush elephant weighs between 4.4 tons and 7.7 tons. What are its least and greatest wieghts rounded to the nearest t

on

2 answers:

VashaNatasha [74]3 years ago

7 0

4.4 rounds to 4.

7.7 rounds to i

WARRIOR [948]3 years ago

6 0

4.4=4 tons rounded

7.7=8 tons rounded

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3 years ago

Which equation gives the number of 1/4 centimeter that are in 7/3 centimeter?

Deffense [45]

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2 years ago

In a circle with a diameter of 25.2 ft, an arc is intercepted by a central angle of 168º.

Rina8888 [55]

Answer:

$36.93\ ft$

Step-by-step explanation:

step 1

Find the circumference of the circle

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step 2

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3 years ago

Pete, a professional bowler, is unhappy with any game below 200. Over time, 80% of his games exceed this score. What is the prob

Aneli [31]

The probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

It has a range of 0 to 1.

It is given that

Pete, a professional bowler, is unhappy with any game below 200

80% of his games exceed this score.

the probability that Pete exceeds 200 in at least 9 of his next 10 games is given by

P( 9/10 > 200) +P(10/10>200)

The binomial experiment consists of n trial out of it x is success.

$P( x) = \dfrac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$

Here p = 0.8

For 9/10 matches

$P( 9/10 > 200) = \dfrac{10!}{9!(10-9)!}0.8^9(1-0.8)^{10-9}\\\\ = {10}(0.8)^9(0.2)\\= 0.268$

For (10/10 >200)

$P( 10/10 > 200) = \dfrac{10!}{10!(10-10)!}0.8^{10} (1-0.8)^{10-10}\\\\ = {1!}(0.8)^{10}\\= 0.1074$

Therefore the probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754.

To know more about Probability

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