Find all solutions in the interval [0, 2π) for 2 sin^2 x = sin x

Mathematics

1 answer:

Ede4ka [16]3 years ago

4 0

Answer:

Step-by-step explanation:

2 sin²x=sin x

2 sin² x-sin x=0

sin x(2 sin x-1)=0

sin x=0

x=0,π

2 sin x-1=0

2 sin x=1

sin x=1/2= sin π/6,sin (π-π/6)

x=π/6,5π/6

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Another way would be to actually solve it.

Let us put into the situation that the unknown variable would be y. The equation then would look like this.

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Then solve

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Step-by-step explanation:

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