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Assoli18 [71]
3 years ago
8

A plane traveled from California and back. It took one hour longer on the way out than it did on the way back. The plane's avera

ge speed out was 300 mph. The average speed on the way back was 350 mph. How many hours did the trip out take? A. 7 hours B. 6 hours C. 13 hours D. 8 hours
Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0

7 hours.....................................

..

andrezito [222]3 years ago
4 0

300t = 350(t-1)

300t = 350t-350

-50t=-350

t = -350 /-50

t = 7 hours

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Solve the system by substitution.<br> y = -4x<br> 23 - 5y = 44
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<h3><u>Explanation</u></h3>
  • Given the system of equations.

\begin{cases} y =  - 4x \\ 23 - 5y = 44 \end{cases}

  • Substitute y = -4x in the second equation.

23 - 5( - 4x) = 44 \\ 23 + 20x = 44 \\ 20x = 44 - 23 \\ 20x = 21 \\ x =  \frac{21}{20}

  • Substitute the value of x in any given equations. I will substitute the value of x in the first equation.

y =  - 4x \Longrightarrow y =  - 4( \frac{21}{20} ) \\ y =   \cancel{ - 4}( \frac{21}{ \cancel{20}} ) \Longrightarrow y =  -  \frac{21}{5}  \\ y =  -  \frac{21}{5}

  • Answer Check by substituting both values in two equations.

<u>First</u><u> </u><u>Equation</u>

y =  - 4x \Longrightarrow  -  \frac{21}{5}  =  - 4( \frac{21}{20} ) \\  -  \frac{21}{5}  =   \cancel{ - 4}( \frac{21}{ \cancel{20}} ) \\  -  \frac{21}{5}  =  -  \frac{21}{5}  \:  \:   \: \checkmark

<u>Second</u><u> </u><u>Equation</u>

23 - 5y = 44 \\ 23 - 5( -  \frac{21}{5} ) = 44 \\23 -  \cancel{5}( -  \frac{21}{ \cancel{5}} ) = 44 \\ 23 + 21 = 44 \\ 44 = 44 \:  \:  \:  \:  \checkmark

Both equations are true for the value of x and value of y.

<h3><u>Answer</u></h3>

<u>\begin{cases} x =  \frac{21}{20}  \\ y =  -  \frac{21}{5}  \end{cases}</u>

<u>Coordinate</u><u> </u><u>Point</u><u> </u><u>form</u>

<u>( \frac{21}{20} , -  \frac{21}{5} )</u>

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Step-by-step explanation:

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