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Lera25 [3.4K]
2 years ago
12

Does anybody know the correct answer to this?

Mathematics
1 answer:
olganol [36]2 years ago
4 0

Answer:

  • sin(X) = 4/5
  • cos(X) = 3/5
  • tan(X) = 4/3

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to help you remember the relations between sides and trig functions in a right triangle.

  Sin(X) = Opposite/Hypotenuse = 24/30 = 4/5

  Cos(X) = Adjacent/Hypotenuse = 18/30 = 3/5

  Tan(X) = Opposite/Adjacent = 24/18 = 4/3

_____

You may be expected to leave the trig ratios in the original unreduced form.

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Write a polynomial function in standard form with zeros at −3, −1, and 1.
Annette [7]

Answer:

f(x) = {x}^{3}  + 3 {x}^{2}  - x -3

Step-by-step explanation:

The given polynomial has zeros at:

x=−3, x=−1, and x=1.

This means that:

x+3, x+1, and x-1 are all factors of this polynomial.

The factored form of this polynomial is :

f(x) = (x + 3)(x + 1)(x - 1)

We expand the last two factors using difference of two squares.

f(x) = (x + 3)( {x}^{2}  - 1)

f(x) = x ( {x}^{2}  - 1) + 3( {x}^{2}  - 1)

f(x) = {x}^{3}  - x+ 3 {x}^{2}  -3

f(x) = {x}^{3}  + 3 {x}^{2}  - x -3

This is the standard form because it is now in decreasing powers of x.

8 0
3 years ago
In the third degree polynomial function f(x) =x^3 + 4x, why are 2i and -2i zeros?
IgorC [24]

Answer:

We just need to evaluate and get f(2i)=0, f(-2i)=0.

Step-by-step explanation:

Since i^2=-1, then i^3=i^2i=-i, and we can apply this when we evaluate f(x) =x^3 + 4x for 2i and -2i.

First we have:

f(2i) =(2i)^3 + 4(2i)=2^3i^3+8i=8(-i)+8i=0

Which shows that 2i is a zero of f(x).

Then we have:

f(-2i) =(-2i)^3 + 4(-2i)=(-2)^3i^3-8i=-8(-i)-8i=8i-8i=0

Which shows that -2i is a zero of f(x).

4 0
3 years ago
If 15% off an item cost 36.21 then what would 100% of the item be?
harina [27]
1-0.15=0.85
36.21/0.85=42.6=ANSWER
3 0
3 years ago
Read 2 more answers
The length of a rectangle is 3 m greater than the width. The area is 108m2. Find the Length and Width
Murljashka [212]
3x =108
X =108/3 =36
Length 36
4 0
3 years ago
Here are two similar cones. The area of ​​the base of the small cone is equal to 36 t cm2. The radius and apothem of the large c
natta225 [31]
V=1/3(pi)(r)^2(h)
V=1/3(pi)(9)^2(15)
V=1/3(3.14)(81)(15)
Then multiply all numbers in parentheses:
3815.1/3=1271.7 cm^3

Hope this Helps!
3 0
3 years ago
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