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3 years ago

Which statement is not true for the function notation of the volume of a cube, V(s) = s3?

Mathematics

1 answer:

Volgvan3 years ago

4 0

<h3>Answer:</h3>

b. The side length of a cube is dependent on the volume.

<h3>Step-by-step explanation:</h3>

The function definition V(s) means the volume (V) is dependent upon the side length (s), <em>not the other way around</em>.

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Haley is camping and needs to go from the campground to the waterfall. She hikes 3 miles north and 7 miles east. What is the sho

miskamm [114]

Answer:

7.61 miles

Step-by-step explanation:

Given that,

Haley hikes 3 miles north and 7 miles east.

We need to find the shortest distance from the campground to the waterfall. Let the distance is D.

It can be calculated as follows :

$D=\sqrt{3^2+7^2}\\D=7.61\ miles$

So, the shortest distance from the campground to the waterfall is 7.61 miles.

3 0

3 years ago

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

3 years ago

Find the radius and circumference of a CD with a diameter of 4.75 inches.

nexus9112 [7]

Radius is half of diameter.
Circumference can be found using the equation C=2(pi)r or C=(pi)d.
r=radius, d=diameter
(pi) is about 3.14 or 22/7

5 0

4 years ago

School Season Ticket Package Football State University $150 for 7 games University of Football $200 for 8 games Gridiron Univers

Alecsey [184]

Football State University = $21.42 for one game

University of Football = $25 for one game

Gridiron University = $29.16 for one game

Sports University = $31.25 for one game

Out of these, Football State University gives the best deal on football tickets.

5 0

4 years ago

Read 2 more answers

A small company 's net income for the first 6 months of the year was 76.500 and for the last six months it was 100,000 . What is

inna [77]

Answer:The ratio of net income in the first 6 months, to the last six months is $76,500 / $100,000. This simplifies intuitively as follows:

76500/100000

Dividing by 100: 765/1000

Dividing by 5: 153/200

The denominator 200 is only divisible by the prime numbers 2 and 5, and since the numerator 153 is not divisible by either 2 or 5, this means that this is in simplest form, and the final answer is 153/200.

Step-by-step explanation:i did the research for you this isnt my own answer therefore don't give me the credit. but hope this helped you tho :D

5 0

3 years ago