Answer: length of wire = 500cm
Step-by-step explanation:
We would determine the volume of material used in making the hollow cylindrical iron pipe by subtracting the volume of the inner pipe from the volume of the outer pipe.
The formula for determining the volume of a cylinder is expressed as
Volume = πr²h
Volume of inner pipe = π × 6² × 35 = 1260π
Volume of outer pipe = π × 8² × 35 = 2240π
Volume of material used in making the hollow cylindrical iron pipe is
2240π - 1260π = 980πcm³
The solid wire made is cylindrical and has a thickness of 2.8cm. This is the diameter. It means that the radius of the wire is 2.8/2 = 1.4cm
Volume of wire = 980πcm³
Applying the volume of cylinder formula, it becomes
980π = π × 1.4² × h
where h = length of wire
h = 980/1.4² = 500cm
Add the radius of the pool to the width of the path to get the radius of the path (15 + 3 = 18). Using 2(pi)r = Circumference, we get 36(pi). If you multiply 36x3.14 you get 103.4 ft.
Answer: Click on your profile at the right corner. Then click on ''Edit Profile'' Then click on ''Profile picture'' then you should see ''Chose File'' once you chose a screen shot you can add it to brainly, the finally Click ''Change!''
Step-by-step explanation:
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u> </u>√15 units
Step-by-step explanation:
Let (6,1) be (x^1,y^1) and (1,-9) be (x^2,y^2) .
As we know ,
Distance(D) = √(x^1-x^2) +(y^1-y^2)
Now,
D= √(x^1-x^2) +(y^1-y^2)
= √(6-1) +(1+9)
= √5+10
= √15 units
: Therefore the distance between (6,1) and (1,-9) is √15 units.
You'll need to calculate the surface area to be painted. The room has two ends, 2 sides and 1 ceiling. The area of the ceiling is 18*20. The area of the two ends of the room is 2(8*18). The area of the two long walls is 2(8*20)
Add these areas together: 18*20 + 2*8*18 + 2*8*20, or 968.
That's 968 square feet. Since each can contains enough paint for 400 square feet of coverage, divide 968 by 400:
968
----- = 2.42. This means having to purchase 2.5 (gallons)
400 This answer is accurate to the nearest 0.5.