Question 7 of 10

The distribution of the amount of money in savings accounts for Florida State students has an average of 1,200 dollars and a sta

Anestetic [448]

Answer:

By the Central Limit Theorem, the sampling distribution of the sample mean amount of money in a savings account is approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Average of 1,200 dollars and a standard deviation of 900 dollars.

This means that $\mu = 1200, \sigma = 900$

Sample of 10.

This means that $n = 10, s = \frac{900}{\sqrt{10}} = 284.6$

The sampling distribution of the sample mean amount of money in a savings account is

By the Central Limit Theorem, approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

7 0

3 years ago

Generate two numerical patterns

Klio2033 [76]

Answer:

vvv

Step-by-step explanation:

2,4,6,8,10

Pattern Rule:Add 2

1,2,4,8,16

Pattern:Multiply by 2

Sorry these were simple.

8 0

2 years ago

Which table represents a function

denpristay [2]

Answer:

The first table

Step-by-step explanation: The x values don't repeat which makes it a function

4 0

3 years ago

Water whose temperature is at 100∘C is left to cool in a room where the temperature is 60∘C. After 3 minutes, the water temperat

Tju [1.3M]

Answer:

21.68 minutes ≈ 21.7 minutes

Step-by-step explanation:

Given:

$T=60+40e^{kt}$

Initial temperature

T = 100°C

Final temperature = 60°C

Temperature after (t = 3 minutes) = 90°C

Now,

using the given equation

$T=60+40e^{kt}$

at T = 90°C and t = 3 minutes

$90=60+40e^{k(3)}$

$30=40e^{3k}$

or

$e^{3k}=\frac{3}{4}$

taking the natural log both sides, we get

3k = $\ln(\frac{3}{4})$

or

3k = -0.2876

or

k = -0.09589

Therefore,

substituting k in 1 for time at temperature, T = 65°C

$65=60+40e^{( -0.09589)t}$

or

$5=40e^{( -0.09589)t}$

or

$e^{( -0.09589)t}=\frac{5}{40}$

or

$e^{( -0.09589)t}=0.125$

taking the natural log both the sides, we get

( -0.09589)t = ln(0.125)

or

( -0.09589)t = -2.0794

or

t = 21.68 minutes ≈ 21.7 minutes

6 0

3 years ago

Keith mows lawns and it takes him 6 hours to mow 4 lawns. How many lawns could be mowed in 32 hours?

Alexeev081 [22]

Answer:

Step-by-step explanation:

If it takes Keith 6 hours to mow 4 lawns, you can find how many lawns he can mow in 32 hours by dividing 32 by 6 and then multiplying the answer by 4. 32/6= ~5.33. This means that since 32 hours is 5.33 times longer than 6 hours, he can mow 5.33 times more lawns. So 5.33*4 = <u>21.33 lawns in 32 hours!</u>

7 0

2 years ago

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