3 years ago

Solve x^2+11X<-8 Urgent please help!!!!!

1 answer:

8 0

Add 121/4 to each side:
x²+11x+121/4 < 121/4-8
x²+11x+121/4 < 89/4
(x+11/2)² < √89/2 ⇒ -√89/2 < x+11/2 < √89/2
-11/2-√89/2 < x < -11/2+√89/2

You might be interested in

The average density of the material in intergalactic space is approximately 2.5 × 10–27 kg/m3. what is the volume of a lead samp

Lesechka [4]

Answer:

e. $1.8\times 10^{-6}m^3$

Step-by-step explanation:

It is given that,

The density of intergalactic space material is $2.5 \times 10^{-27}$ kg per cubic meter.

And the volume of intergalactic space material is $8.0\times 10^{24} m^3$

So the mass of that much intergalactic space material is,

$m= \rho\times v$ , where 'm' is the mass, and 'v' is the volume.

Putting the values we get,

$m=2.5 \times 10^{-27}\times 8.0 \times 10^{24}$

$m=20\times 10^{(-27+24)}=20\times 10^{-3} kg$

It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is $20 \times 10^{-3}=2 \times 10^{-2}kg$

So the volume of lead is,

$v=\frac{m}{\rho} =\frac{2 \times 10^{-2}}{11300} = 0.00000177 m^3$

$v=1.77 \times 10^{-6}=1.8\times 10^{-6}m^3$

So the volume of lead is $v=1.8\times 10^{-6}m^3$ .

3 0

3 years ago

I really Need help on this question, I have soo much homework to do, and i cant get it done if i have questions like this stoppi

SIZIF [17.4K]

i'ma go with Constant on the first box

second box i think( again terrible at this) is selemas initial distance from home

8 0

3 years ago

Read 2 more answers

Cedric had 2,204 baseball cards that he wanted to sell. He sold them in packages of 4 and charged $2.25 for each package. If he

Dmitry [639]

He would make $1239.75

divide 4 in 2,204

multiply by 2.25

4 0

3 years ago

Read 2 more answers

Complete the statement.

Ne4ueva [31]

I am pretty sure that the answer is 3

6 0

3 years ago

Read 2 more answers

Solve for x.<br> 3(3x - 1) + 23 - x) = 0

enot [183]

9x-3+69-3x=0
6x+66=0
6x=-66
X=-11

3 0

3 years ago