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3 years ago

How can you solve 0=v+12

2 answers:

8 0

Hi again!

0 = v + 12

They want you to learn how to flip the equation.

v + 12 = 0

Subtract 12 on both sides

v + 12 - 12 = 0 - 12

v = - 12

Let me know if you have any questions!

Aleks04 [339]3 years ago

4 0

Subtract 12 from both sides
-12 = v
Hope this helps!

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3 years ago

Read 2 more answers

Through (4,-4) ; perpendicular to 6y=x-12

BARSIC [14]

y = mx + b

m = slope and b = y-intercept

We can arrange 6y = x - 12 in the form of y = mx + b

6y = x - 12

y = 1/6(x) - 2

Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.

Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

y = -6x + b

To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

-4 = -6(4) + b

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So the equation for the perpendicular line is y = -6x + 20

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3 years ago

Find the coordinates of the point where the line <img src="https://tex.z-dn.net/?f=y%3D5x%2B7%5C%5C" id="TexFormula1" title="y=5

Anvisha [2.4K]

Answer:

(0, 7)

Step-by-step explanation:

The point that crosses the y-axis is called the y-intercept of the line.

We are given an equation of the line and we need to determine the y-intercept. This can be done by determining the constant in the equation.

What are constants?

Constants are such terms that include only numbers. There should be no variables in constants.

$\bullet \ \text{Given equation of line: y = 5x + 7}$

The constant we can see in the equation is "7". Therefore, the y-intercept is 7.

Note: The y-intercept of the line must have an x-coordinate of 0.

<u>Therefore,</u>

⇒ Coordinates of y-intercept: (x, y) ==> (0, 7).

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2 years ago