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Georgia [21]
3 years ago
6

Through (4,-4) ; perpendicular to 6y=x-12

Mathematics
1 answer:
BARSIC [14]3 years ago
3 0

y = mx + b

m = slope and b = y-intercept


We can arrange 6y = x - 12 in the form of y = mx + b

                  6y = x - 12

                    y = 1/6(x) - 2

Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.

Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

                  y = -6x + b

To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

                -4 = -6(4) + b

                 b = -4 + 6(4)

                 b = -4 + 24

                 b = 20

So the equation for the perpendicular line is y = -6x + 20

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\frac{1}{4} → a

the equation is y = mx ( where m is the slope / constant of variation )

calculate m using the gradient formula

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with (x₁, y₁) = (0, 0 ) and (x₂, y₂ ) = (4, 1) ← 2 points on the line

m = \frac{1-0}{4-0} = \frac{1}{4}


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svetoff [14.1K]

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Step-by-step explanation:

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