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TEA [102]
3 years ago
11

36 ÷ 3^2 +4*2-1 can u help me get the answer?

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0

36 ÷ 3^2 +4*2-1

36/9+8-1

4+7

11

spin [16.1K]3 years ago
6 0
<span>36 ÷ 3^2 +4*2-1
</span>=36 ÷ 9 + 4*2-1<span>
=</span>4 + 8 - 1
= 11

USING PEMDAS
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On a given day, 36 of the 445 students in a school were absent. What was the appproximate absentee rate that day?
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Answer: The approximate absentee rate that day would be 8.09%.

Step-by-step explanation:

Since we have given that

Number of students who were absent = 36

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Rate of absentee of that day would be

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3 years ago
When you find the surface area of a cube, you ________ the length of the cube and multiply by 6.
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A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th
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Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

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Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

A = a + (A \cap B)

In which a is the probability that he wins the first race but not the second and A \cap B is the probability that he wins both these races.

By the same logic, we have that:

B = b + (A \cap B)

The probability that he wins both races is 0.5.

This means that A \cap B = 0.5

The probability that he wins the second race is 0.6

This means that B = 0.6

B = b + (A \cap B)

0.6 = b + 0.5

b = 0.1

The probability that he wins the first race is 0.7.

This means that A = 0.6

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A) he wins at least one race.

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P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

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C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

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