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3 years ago

What is the value of x in the equation 3(2x + 8) = 0? –8 –4 4 8

2 answers:

7 0

3(2x+8)=0

Simplify both sides of the equation.

3(2x+8)=0

(3)(2x)+(3)(8)=0(Distribute)

6x+24=0

Subtract 24 from both sides.

6x+24−24=0−24

6x=−24

Divide both sides by 6.

6x/6 = −24/6

x=−4

avanturin [10]3 years ago

7 0

You said 3 (2x + 8) = 0

Divide each side by 3 : 2x + 8 = 0

Subtract 8 from each side: 2x = - 8

Divide each side by 2 : x = - 4

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Historical data for a local manufacturing company show that the average number of defects per product produced is 2. In addition

charle [14.2K]

Answer:

The probability that there will be a total of 7 defects on four units is 0.14.

Step-by-step explanation:

A Poisson distribution describes the probability distribution of number of success in a specified time interval.

The probability distribution function for a Poisson distribution is:

$P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}, x=0,1,2,3,...$

Let X = number of defects in a unit produced.

It is provided that there are, on average, 2 defects per unit produced.

Then in 4 units the number of defects is, $(2\times4)=8$ .

Compute the probability of exactly 7 defects in 4 units as follows:

$P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}\\P(X=7)=\frac{e^{-8}8^{7}}{7!}\\=\frac{0.0003355\times2097152}{5040}\\ =0.1396\\\approx0.14$

Thus, the probability of exactly 7 defects in 4 units is 0.14.

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