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Pani-rosa [81]
3 years ago
5

Simplify. 10^−4 10,000 0.0001 1,000 0.00001

Mathematics
2 answers:
Alina [70]3 years ago
5 0
<span>10^−4 = 1 / 10^4 = 0.0001
answer
</span><span>0.0001</span>
elena-14-01-66 [18.8K]3 years ago
3 0
Your answer is, .0001 because you move ur decimal from the back of the ten four times and place it
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A searchlight uses a parabolic mirror to cast a beam of light in parallel rays where the light bulb is located at the focus of t
Vitek1552 [10]

Answer:

the third option

Step-by-step explanation:

Our equation is

{y}^{2}  = 36(x - 10)

Equation of a vertical parabola is

( {y - k)}^{2}  = 4p(x  - h)

where (h,k) is the center

The focus is

(h+p, k)

Equation of directrix is

x= h-p,

Here the center is (10,0)

Next, we factor out 4 in the original equation

4(9)

So we have

{y}^{2}  = 4(9)(x - 10)

So our p=9,

So our focus is

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The third option is the answer

3 0
2 years ago
Need Help on this ASAP Geometry
navik [9.2K]
You calculate it by taking the change in y's over the change in x's. So (y1-y2)/(x1-x2). You get the equation (-5 - 3)/(5 - 7) which equals 4. 4 is the slope.
7 0
4 years ago
Read 2 more answers
Please help me answer this question
lbvjy [14]

A. Let s be the smallest integer
B. We must add 2 to get the next greater integer
C. Second integer is s+2
D. s+(s+2)=118
2•s+2=118
2s+2-2=118-2
2s=116
2s/2=116/2
s=58
If the smallest even integer is 58 the consecutive integer is 58+2=60
Verify
58+60=118 ✔️
7 0
3 years ago
Find the slope of the passing line through the points (5,-8) and (2,-3)
Hatshy [7]

Answer:

-5/3

Step-by-step explanation:

-8--3=-5

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4 0
3 years ago
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Write an equation for the nth term of the geometric sequence 3584, 896, 224... Find the sixth term of this sequence
lions [1.4K]

Answer:

Step-by-step explanation:

r = \frac{a_n}{a_{n-1}} = \frac{896}{3584} =  \frac{1}{4}

Using the geometric series formula for the <em>n</em>th term:

S_n = a \cdot \frac{1-r^n}{1-r} => S_{6} = 3584 \cdot \frac{1 - (\frac{1}{4})^{6} }{1 - \frac{1}{4} }  = 4777\frac{1}{2}

4 0
4 years ago
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