Answer :
no. of days used to repair 1250m of road = 5
no. of days used to repair 1m of road = 5/1250
no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days
V=12, comment if u need an explanation
I think it's true because its the same data set just put in order backwards.
Hope this helps!! :-)
The answer is 10x+9y+6 if your trying to combine all like terms.
-36 because 64-100 (separate the terms)
