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aivan3 [116]
3 years ago
15

1,4,5,6,6,7,8 quartile

Mathematics
1 answer:
Softa [21]3 years ago
3 0
What is your question?

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Help<br> Please .............
wlad13 [49]
524
This is answer
Because 524/100=5.24
6 0
2 years ago
What is the measurement of the highlighted side x? Please help and show steps please :)
Soloha48 [4]

Answer:

Denote the O, A, B, C, D as shown in attached image:

O is center of circle.

OA = OC = OD = radius of circle

=> triangle OAD is isosceles

=> BA = BD = 12.8

Applying Pythagorean theorem:

OB = sqrt(OA^2 - BA^2) = sqrt(15.1^2 - 12.8^2) = 8.0

=> x = OC - OB = 15.1 - 8.0 = 7.1

Hope this helps!

:)

8 0
3 years ago
What is 5 and one fourth times three
Ilya [14]
5 and 1/4 times 3. 1/4 is equal to .25. So, 5.25 x 3 is...
15.75
7 0
3 years ago
Read 2 more answers
Solve the system of equations. \begin{aligned} &amp; -5x+13y = -7 \\\\ &amp; 5x+4y=24 \end{aligned} ​ −5x+13y=−7 5x+4y=24 ​ x= e
riadik2000 [5.3K]

Answer:

The solution of the given equations

x =4 , y = 1

Step-by-step explanation:

<u>Explanation</u>:-

<u>Step(l</u>):-

Given the system of equations -5x+13y = -7 ..(l)

                                                     5x+4y=24 ..(ll)

<u>Step(ll)</u>

Adding (l) and (ll) equations and cancelling '5x' terms we get

         13y+4y = -7 +24

               17y = 17

dividing '17' on both sides, we get

                y=1

<u>Step(lll):-</u>

Substitute y=1 in equation (l) , we get

-5x+13y = -7

-5x + 13(1) = -7

subtracting '13' on both sides, we get

-5x +13 -13= -7 -13

-5x = -20

Dividing '-5' on  both sides, we get

x = \frac{-20}{-5}

x = 4

<u>Conclusion</u>:-

The solution of the given equations

x =4 , y = 1

7 0
3 years ago
PLS HELP 1!1!!1!1!1!1!1!1!
kap26 [50]

The area of the Logo 1 will be 12.48 square meters and the area of the Logo 2 will be 9.6 square meters.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Now consider the logos for Parkside Printing shown.

Determine the actual area of Logo 1  and Logo 2 in square meters will be

The area of the Logo 1 (A₁) will be

\rm A _1 = 12 \times 8 - 6 \times 3\\\\A_1 = 78 \ cm^2\\\\A_1 = 78 \times 0.16 \ m^2\\\\ A_1 = 12.48 \ m^2

Then the area of the Logo 2 (A₂) will be

\rm A_2 = \dfrac{1}{2} \times 12 \times 10\\\\A_2 = 60 \ cm^2\\\\A_2 = 60 \times 0.16 \ m^2\\\\A_2 = 9.6 \ m^2

More about the geometry link is given below.

brainly.com/question/7558603

#SPJ1

8 0
2 years ago
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