1,4,5,6,6,7,8 quartile

The circumference of a circle is 18 pi inches what is the radius in inches of the circle

Ne4ueva [31]

The radius would be 9 using the formula C=2r

3 0

3 years ago

Leon charged $75 at an interest rate of 12.5%. How much will Leon have to pay after one month if he makes no payments

pav-90 [236]

I believe that the question is assuming this is taking place over one month here is what I think you would do.

1) 75/12.5 = 6
2) add that answer to 75, so 75+6, and you get 81

7 0

3 years ago

The quotient of a number X and 2 is 20

Maurinko [17]

X÷2=20. Want an explanation?

6 0

3 years ago

In ∆XYZ, m∠X = 152, y = 15, and z = 19. Find side x and the measure of angle Y to the nearest tenth

solong [7]

The measure of the side $x$ is approximately 33 and the measure of angle $Y$ is approximately 12.321°.

<h3>How to find a missing angle in a triangle by law of sine and law of cosine</h3>

In this problem we must apply the law of cosine and the law of sine to determine the angle Y:

<h3>Law of cosine</h3>

$x = \sqrt{y^{2}+z^{2}-2\cdot y\cdot z\cdot \cos X}$

$x = \sqrt{15^{2}+19^{2}-2\cdot (15)\cdot (19)\cdot \cos 152^{\circ}}$

$x \approx 33$

$\frac{\sin Y}{y} = \frac{\sin X}{x}$

$Y = \sin^{-1}\left(\frac{y}{x}\cdot \sin X \right)$

$Y = \sin^{-1}\left(\frac{15}{33}\cdot \sin 152^{\circ} \right)$

$Y \approx 12.321^{\circ}$

The measure of the side $x$ is approximately 33 and the measure of angle $Y$ is approximately 12.321°. $\blacksquare$

To learn more on triangles, we kindly invite to check this verified question: brainly.com/question/25813512

7 0

2 years ago

An 8-sided die is formed when two square pyramids are attached by their bases. The perimeter of the base shape is 6 centimeters.

lawyer [7]

Answer:

7.5cm²

Complete question:What is the surface area of the 8-sided figure?

Step-by-step explanation:

Consider the half of the 8-sided die i.e the pyramid ABCDE:

As the base is 6 of the perimeter, so each side of the base is 6/4=3/2

Now, the distance between the tallest points is 2 cm, so the height of Pyramid ABCDE is 1 cm.

Considering the right triangle EOM:

EO=1, OM= 3/4 (it is half of AB=3/2) and EM is the hypothenuse, so by the pythagorean theorem length of EM is

$\sqrt{1+ ( \frac{3}{4} )^{2} }= \sqrt{1+ \frac{9}{16} }= \sqrt{ \frac{25}{16} }= \frac{5}{4} (cm)$

5. So side EBC has area

$\frac{1}{2}BC*EM= \frac{1}{2}* \frac{3}{2}* \frac{5}{4}= \frac{15}{16}$

6. The total area is 8*Area(EBC)= $8* \frac{15}{16}= \frac{15}{2}=7.5 ( cm^{2} )$

3 0

3 years ago