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Yakvenalex [24]
3 years ago
7

1. Determine the zeros of f(x) = x3 – 3x2 – 16x + 48? Somebody explain it please?:/

Mathematics
1 answer:
inn [45]3 years ago
6 0
x^{2} -  3x^{2} - 16x + 48 = 0

x^{2} (x - 3) - 16(x - 3) = 0

(x - 3) ( x^{2} - 16) = 0

(x - 3) (x - 4) (x + 4) = 0

x = -4, 3, 4

The zeros are: -4, 3, 4
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