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grandymaker [24]

2 years ago

5

The scatterplot shows the relationship between a player’s level in a game and the point total in the level answer the question a

bout the scatterplot

1 answer:

goldfiish [28.3K]2 years ago

5 0

Answer:

(pictures of answers below)

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Find f (2b^2) for (x)=x^2-4x

BlackZzzverrR [31]

Answer:

A

Step-by-step explanation:

We are given the function:

$f(x) = x^2 - 4x$

And we want to find:

$\displaystyle f(2b^2)$

Substitute:

$\displaystyle f(2b^2) =(2b^2)^2 -4(2b^2)$

And evaluate:

$\displaystyle \begin{aligned} f(2b^2) &=(2b^2)^2 -4(2b^2) \\ &=(4b^4) +(-8b^2) \\ &= 4b^4 - 8b^2 \end{aligned}$

In conclusion, our answer is A.

7 0

3 years ago

A^8/a^3 <br> hey can someone help me

Stells [14]

A^8/a^3=a^5 you subtract the exponents

3 0

2 years ago

Given the figure below, find the values x of and z.

kkurt [141]

Answer:

x=7

z=79

Step-by-step explanation:

13x+10=101

13x=91

x=7

180-101=79

6 0

2 years ago

During February, Kevin will water has ivy every third day, and water his cactus every fifth day. On which date will Kevin first

noname [10]

Ok I’m bout to help you get this answer

5 0

2 years ago

1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg

tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

$d=\sqrt{x^2+y^2}$

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

$\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}$

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute :

$d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}$

$d=1\ km$

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

$\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20$

Thus we have

$x.x'+y.y'=20$

Solving for x'

$\displaystyle x'=\frac{20-y.y'}{x}$

Since y'=-60

$\displaystyle x'=\frac{20+0.6(60)}{0.8}$

$x'=70\ km/h$

The SUV is running at 70 km/h

7 0

3 years ago