3 years ago

How do I solve for n: 21k-3n+9p> 3p+12

Mathematics

1 answer:

Travka [436]3 years ago

5 0

$21k-3n+9p\ \textgreater \ 3p+12\\21k+6p+12\ \textgreater \ 3n\\n\ \textless \ 7k+2p+4$

n<7k+2p+4

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