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4 years ago

How do I solve for n: 21k-3n+9p> 3p+12

Mathematics

1 answer:

Travka [436]4 years ago

5 0

$21k-3n+9p\ \textgreater \ 3p+12\\21k+6p+12\ \textgreater \ 3n\\n\ \textless \ 7k+2p+4$

n<7k+2p+4

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3 years ago

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3 years ago

Josie spent 4/7 of ten money in her purse on some books, and the rest of the money on 18 markers. Each marker cost $1.20. How mu

NeTakaya

Let's assume money in Josie's purse to begin with as 'x'

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3 years ago

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Anvisha [2.4K]

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Step-by-step explanation:

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3 years ago

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IrinaK [193]

The answer to this question is 50

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3 years ago

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