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4 years ago

Identify any values of data that might affect the statistical measures of spread and center.

Mathematics

1 answer:

monitta4 years ago

5 0

Answer: There is a high data value that causes the data set to be asymmetrical for the males.

The females 'might' have an outlier, but it's difficult to say exactly.

An outlier is defined as any data value greater than 1.5 times the Interquartile range or less.

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Please help me with this

Cerrena [4.2K]

Answer:

Yes;Each side of triangle PQR is the same length as the corresponding side of triangle STU

Step-by-step explanation:

You can observe the sides of both triangles to see if this property holds

Lets check the length of AB

A(0,3) and B(0,-1)

$AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\\\\\AB=\sqrt{(0-0)^2+(-1-3)^2} \\\\\\\\AB=\sqrt{0^2+-4^2} \\\\\\AB=\sqrt{16} =4units$

Now check the length of the corresponding side DE

D(1,2) and E(1,-2)

$DE=\sqrt{(1-1)^2+(-2-2)^2} \\\\\\DE=\sqrt{0^2+-4^2} \\\\\\DE=\sqrt{16} =4units$

The side AB has the same length as side DE.This is also true for the remaining corresponding sides.

6 0

4 years ago

Write the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5)

Sedbober [7]

Answer: $\bold{y=-\dfrac{1}{3}x-1}$

<u>Step-by-step explanation:</u>

(4, 1) & (2, -5)

First, find the slope (m) and then the perpendicular (opposite reciprocal) slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\\m=\dfrac{-5-1}{2-4} = \dfrac{-6}{-2}=3\quad \rightarrow \quad m_{\perp}=-\dfrac{1}{3}\\$

Next, find the midpoint of (4, 1) and (2, -5):

$Midpoint=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{4+2}{2},\dfrac{1-5}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{6}{2},\dfrac{-4}{2}\bigg)\\\\\\.\qquad \qquad=(3, -2)$

Lastly, input the perpendicular slope and the midpoint into the Point-Slope formula to find the equation of the line:

$y - y_1 = m_{\perp}(x - x_1)\\\\y - (-2) = -\dfrac{1}{3}(x - 3)\\\\y + 2=-\dfrac{1}{3}x +1\\\\y =-\dfrac{1}{3}x - 1\\$

6 0

3 years ago

In a statistics class there are 18 juniors and 10 seniors; 6 of the seniors are females and 12 of the juniors are males. If a st

Natasha_Volkova [10]

Answer:

P(a junior or a senior)=1

Step-by-step explanation:

The formula of the probability is given by:

$P(A)=\frac{n(A)}{N}$

Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.

In this case, N is the total number of the students of statistics class.

N=18+10=28

The probability of the union of two mutually exclusive events is given by:

$P(AUB)=P(A)+P(B)$

Therefore:

P(a junior or a senior) =P(a junior)+P(a senior)

Because a student is a junior or a senior, not both.

n(a junior)=18

n(a senior)=10

P(a junior)=18/28

P(a senior) = 10/28

P(a junior or a senior) = 18/28 + 10/28

Solving the sum of the fractions:

P(a junior or a senior) = 28/28 = 1

4 0

3 years ago

1. Given the following relation, determine the inverse relation.

gayaneshka [121]

Answer:

1. a

2. $f^{-1} (x)=\frac{x}{2} +2$

Step-by-step explanation:

1. Since there is one value of y for every value of x in (−1,0),(−4,5),(3,2),(−3,5), this relation is a function.

2. To find the inverse, interchange the variables and solve for y.

$f^{-1} (x)=\frac{x}{2} +2$

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=2x%20%7B%20%7D%5E%7B2%7D%20%20%2B%205x%20-%203" id="TexFormula1" title="2x { }^{2} + 5x - 3"

Kaylis [27]

If you’re factoring it, it’s

(2x - 1) (x+3)

5 0

3 years ago