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Alex Ar [27]
3 years ago
7

The box plot shows the total amount of time, in minutes, the students of a class spend reading each day:

Mathematics
2 answers:
ELEN [110]3 years ago
8 0
<h2>Answer:</h2>

The information that is provided by the box plot is:

                  The median for the data.

<h2>Step-by-step explanation:</h2>

Clearly after looking at the box and whisker plot we observe that:

The starting point of the whisker gives us the minimum value of the data i.e. '1'

The starting point of the box gives us the first or lower quartile i.e. Q_1=3

The middle of the box gives us the middle quartile or median i.e. Q_2=5

The end point of the box gives us the upper or third quartile i.e. Q_3=7.5

The end point of the whisker gives us the maximum value of the data i.e. '10'

         Hence, we obtain the median of the data.

vova2212 [387]3 years ago
5 0
I am PRETTY sure that the answer is "The number of students who provided information." I do not know for sure, so don't hold it against me if I was wrong.
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\begin{array}{c}\\\left( \begin{array}{l}\\{\rm{Positive Predictive }}\\\\{\rm{value}}\left( {PPV} \right)\\\end{array} \right) = \frac{{{\rm{Prevalence}} \times {\rm{Sensitivity}}}}{{\left( {{\rm{Prevalence}} \times {\rm{Sensitivity}}} \right) + \left( {{\rm{1 - Prevalence}} \times 1 - {\rm{Specificity}}} \right)}}\\\\ = \frac{{0.1 \times 0.60}}{{\left( {0.1 \times 0.60} \right) + \left( {1 - 0.1 \times 1 - 0.70} \right)}}\\\\ = \frac{{0.06}}{{0.33}}\\\\ = 0.181818\\\\ = 0.182{\rm{ }}\left( {{\rm{Round to 3 decimal place}}} \right)\\\end{array}  

(Positive Predictive  value, PPV) =

(Prevalence×Sensitivity)/Prevalence×Sensitivity +(1−Prevalence×1−Specificity)  

=   (0.1×0.60)/0.1×0.60  + (1−0.1×1−0.70) ​  

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(Positive Predictive  value, PPV) = 0.182 (3decimals)    

We have to convert the PPV into percentage,

\begin{array}{c}\\PPV = 0.182 \times 100\\\\ = 18.2\% \\\end{array}  

PPV=0.182×100

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Therefore, the predictive positive value is 18.2%.

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